A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction? O A. 5-membered rhodacycle ring is formed O B. 6-membered rhodacycle ring is formed O C. the two units of C=C are reduced to alkane C-C bond. O D. the two units of C=C are inserted to the rhodium metal centre

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Chapter21: Transition Metals And Coordination Chemistry
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A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction?
O A. 5-membered rhodacycle ring is formed
O B. 6-membered rhodacycle ring is formed
O C. the two units of C=C are reduced to alkane C-C bond.
O D. the two units of C=C are inserted to the rhodium metal centre
Transcribed Image Text:A rhodium metal centre undergoes cyclometallation with two units of C=C, what is the expected product of this reaction? O A. 5-membered rhodacycle ring is formed O B. 6-membered rhodacycle ring is formed O C. the two units of C=C are reduced to alkane C-C bond. O D. the two units of C=C are inserted to the rhodium metal centre
Why can an organometallic complex perform the reactions such as insertion where normal coordination complex could not perform?
O A. Because of the intramolecular pi-electron charge transfer in the ligand.
OB.
Because of the intermolecular pi-electron charge transfer in the ligand.
Because the presence of dorbitals in the metal centre.
O D. Because of the metal to ligand pi-electron charge transfer.
Transcribed Image Text:Why can an organometallic complex perform the reactions such as insertion where normal coordination complex could not perform? O A. Because of the intramolecular pi-electron charge transfer in the ligand. OB. Because of the intermolecular pi-electron charge transfer in the ligand. Because the presence of dorbitals in the metal centre. O D. Because of the metal to ligand pi-electron charge transfer.
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