A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length ( L=0.46 m) and the same area (A =0.13 cm?). In the considered system, chromium is joined to the left hand which is at Te =74.8 C, whereas copper is in physical contact with the right end at Toh =7°C. The thermal conductivity constants of the materials are given as k, = 93.7 W/(m-K) and k, = 401 W/(m K). ASsuming steady state is eventually achieved, answer the following questions. %3D right a) Evaluate the junction temperature between the two layers. Tunction = b) Calculate the rate of heat flow (power) through conduction in SI units. P= J/s Twrt Layer 1 Layer 2 Trght Check

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter28: Current And Resistance
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A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length (
L=0.46 m) and the same area (A = 0.13 cm²), In the considered system, chromium is joined to the left hand which is at
Te =74.8 C, whereas copper is in physical contact with the right end at Toh =7C. The thermal conductivity constants of
the materials are given as k, = 93.7 W/(m K) and k, = 401 W/ (m · K). Assuming steady state is eventually achieved, answer
the following questions.
a) Evaluate the junction temperature between the two layers. Tunction=
J/s
b) Calculate the rate of heat flow (power) through conduction in SI units. P=
Tuft
Layer 1
Layer 2
Trght
Check
Next page
Jump to.
Transcribed Image Text:A rod is made of two different layers: chromium and copper; as shown in the diagram below. Both layers have the same length ( L=0.46 m) and the same area (A = 0.13 cm²), In the considered system, chromium is joined to the left hand which is at Te =74.8 C, whereas copper is in physical contact with the right end at Toh =7C. The thermal conductivity constants of the materials are given as k, = 93.7 W/(m K) and k, = 401 W/ (m · K). Assuming steady state is eventually achieved, answer the following questions. a) Evaluate the junction temperature between the two layers. Tunction= J/s b) Calculate the rate of heat flow (power) through conduction in SI units. P= Tuft Layer 1 Layer 2 Trght Check Next page Jump to.
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