Problem 5.1A rotational spring-mass system is shown to the right. The slender rigid barhas a mass of 18 kg and a length of { = 1.5 m. The springs have stiffness k =360 N/m. The bar has a displacement of –0.06 rad and a speed of –1.1 rad/swhen a harmonic moment M (t) = (80 N·m)cos 16t is applied. Find theresponse of the system. Assume small displacements. You will need to solvethe differential equation because the results from lecture and in the book arefor M(t) = M sin wt, not M (t) = Mo cos wt. You do not have to derivethe homogeneous solution from scratch; you may use equations from Module3, but the coefficients will be different.k-3Мо cos otAnswer: 0 (t) = {0.0540 cos 10t – 0.110 sin 10t0.114 cos 16t} radk

Springs generally deform under an applied force. This deformation is a function of nature of force.…

A rotational spring-mass system is shown to the right. The slender rigid bar nas a mass of 18 kg and a length of l = 1.5 m. The springs have stiffness k = 360 N/m. The bar has a displacement of -0.06 rad and a speed of -1.1 rad/s when a harmonic moment M(t) = (80 N•m)cos 16t is applied. Find the response of the system. Assume small displacements. You will need to solve he differential equation because the results from lecture and in the book are or M(t) = Mo sin wt, not M (t) = Mo cos wt. You do not have to derive he homogeneous solution from scratch; you may use equations from Module 3, but the coefficients will be different. 2l 3 Mo cos wt Answer: 0(t) ={0.0540 cos 10t 0.110 sin 10t – 0.114 cos 16t} rad

A rotational spring-mass system is shown to the right. The slender rigid bar nas a mass of 18 kg and a length of l = 1.5 m. The springs have stiffness k = 360 N/m. The bar has a displacement of -0.06 rad and a speed of -1.1 rad/s when a harmonic moment M(t) = (80 N•m)cos 16t is applied. Find the response of the system. Assume small displacements. You will need to solve he differential equation because the results from lecture and in the book are or M(t) = Mo sin wt, not M (t) = Mo cos wt. You do not have to derive he homogeneous solution from scratch; you may use equations from Module 3, but the coefficients will be different. 2l 3 Mo cos wt Answer: 0(t) ={0.0540 cos 10t 0.110 sin 10t – 0.114 cos 16t} rad

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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