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A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.47 MPa and a sample standard deviation of 0.76 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) MPa Interpret this bound. O with 95% confidence, we can say that the value f the true mean proportional limit stress of all such joints is centered around this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is less than this value. O with 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is greater than this value. What, if any, assumptions did you make about the distribution of proportional limit stress? O We must assume that the sample observations were taken from a chi-square distributed population. O We do not need to make any assumptions. O We must assume that the sample observations were taken from a normally distributed population. O We must assume that the sample observations were taken from a uniformly distributed population. (b) Calculate and interpret a 95% lower prediction bound for proportional limit stress of a single joint of this type. (Round your answer to two decimal places.) MPa Interpret this bound. O If this bound is calculated for sample after sample, in the long run, 95% of these bounds will provide a lower bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will provide a higher bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will be centered around this value for the corresponding future values of the proportional limit stress of a single joint of this type.

A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.47 MPa and a sample standard deviation of 0.76 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) MPa Interpret this bound. O with 95% confidence, we can say that the value f the true mean proportional limit stress of all such joints is centered around this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is less than this value. O with 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is greater than this value. What, if any, assumptions did you make about the distribution of proportional limit stress? O We must assume that the sample observations were taken from a chi-square distributed population. O We do not need to make any assumptions. O We must assume that the sample observations were taken from a normally distributed population. O We must assume that the sample observations were taken from a uniformly distributed population. (b) Calculate and interpret a 95% lower prediction bound for proportional limit stress of a single joint of this type. (Round your answer to two decimal places.) MPa Interpret this bound. O If this bound is calculated for sample after sample, in the long run, 95% of these bounds will provide a lower bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will provide a higher bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will be centered around this value for the corresponding future values of the proportional limit stress of a single joint of this type.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.47 MPa and a sample standard deviation of 0.76 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) MPa Interpret this bound. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is centered around this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is less than this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is greater than this value. What, if any, assumptions did you make about the distribution of proportional limit stress? O We must assume that the sample observations were taken from a chi-square distributed population. O We do not need to make any assumptions. O We must assume that the sample observations were taken from a normally distributed population. O We must assume that the sample observations were taken from a uniformly distributed population. (b) Calculate and interpret a 95% lower prediction bound for proportional limit stress of a single joint of this type. (Round your answer to two decimal places.) MPa Interpret this bound. O If this bound is calculated for sample after sample, in the long run, 95% of these bounds will provide a lower bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will provide a higher bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will be centered around this value for the corresponding future values of the proportional limit stress of a single joint of this type.
Transcribed Image Text:A sample of 20 joint specimens of a particular type gave a sample mean proportional limit stress of 8.47 MPa and a sample standard deviation of 0.76 MPa. (a) Calculate and interpret a 95% lower confidence bound for the true average proportional limit stress of all such joints. (Round your answer to two decimal places.) MPa Interpret this bound. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is centered around this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is less than this value. O With 95% confidence, we can say that the value of the true mean proportional limit stress of all such joints is greater than this value. What, if any, assumptions did you make about the distribution of proportional limit stress? O We must assume that the sample observations were taken from a chi-square distributed population. O We do not need to make any assumptions. O We must assume that the sample observations were taken from a normally distributed population. O We must assume that the sample observations were taken from a uniformly distributed population. (b) Calculate and interpret a 95% lower prediction bound for proportional limit stress of a single joint of this type. (Round your answer to two decimal places.) MPa Interpret this bound. O If this bound is calculated for sample after sample, in the long run, 95% of these bounds will provide a lower bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will provide a higher bound for the corresponding future values of the proportional limit stress of a single joint of this type. O If this bound is calculated for sample after sample, in the long run 95% of these bounds will be centered around this value for the corresponding future values of the proportional limit stress of a single joint of this type.
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