A sample of 25 bottles of orange juice were measured and the sample standard deviation is 1.8 ounces. Use the information to develop a 90% confidence interval estimate of the variance of the population. In the following box, type the upper bound of the interval. Keep 2 decimals.

Q: A recent national survey found that high school students watched an average (mean) of 7.2 movies per…

A: Solution: 1. State the hypotheses. Null hypothesis: That is, the college students watch not fewer…

Q: A sample of 28 was taken from a population, and r = .45. What is the 95% confidence interval for the…

A: Correlation coefficient: Correlation analysis is used to measure strength of the association between…

Q: How many more Tweets are students at Hempstead High School sending in 2017 than in 2012? The table…

A: If an interval is proposed as an estimate of the unknown parameter, then it is interval estimation.…

Q: Use he given confidence Interval to find the margin of error and the sample proportion.…

A: Given Data Lower limit = 0.786 upper limit = 0.810

Q: ne manager of the local health club is interested in determining the number of times members use the…

A: Given data,n=15x=11.2s=3.2α=0.05df=n-1=14t-critical value at df=14 and α=0.05 is tc=2.145

Q: A consumer advocacy group suspects that a local supermarket's 7-ounce packages of cheddar cheese…

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Q: The bottlers of a new fruit juice daily select a random sample of 12 bottles of the drink to…

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Q: The owner of the AGT Gas Station wishes to determine the fraction of customers who pay using a…

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Q: If you were constructing a 95% confidence interval of the population mean based on a sample of n =…

A: Obtain the critical value of t. The critical value of t is obtained below: Obtain the degrees of…

Q: In a manufacturing process, a random sample of 19 manufactured bolts has a mean length of 3.2 inches…

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Q: Find the critical value, for a 90% confidence when the sample size is 22.

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Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

A: GivenPopulation standard deviation is knownThe variable under consideration is very close to being…

Q: Determine the 99.5 percent confidence interval that contains the population variance if the sample…

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Q: Find the 98% confidence interval for the difference between the means of the two populations

A: Given that sample size n = 18 Mean difference = 22.9 And SD sd = 2.2 The critical value of t at (n -…

Q: For an SRS of 66 students, the average exam score was a 73. Assume you know the population standard…

A: Given,Standard deviation(σ)=10margin of error(E)=1.0α=1-0.99=0.01α2=0.005Z0.005=2.58     (from…

Q: Find the 90 percent confidence interval for the variance and standard deviation for the time it…

A: Solution :  Given : n = 27             s = 8.9 minutes             α = 0.1 Confidence interval for…

Q: find the t/α2 value for a 98% confidence interval for the mean when the sample size is 39.  t/α2=

A: The objective is to find the critical value for 98% confidence interval for the mean.

Q: Experience has shown that the weight of lemons produced by an orchard is normally distributed, with…

A: The standard error is given by: S.E.=σn Here, n = 115, σ = 8.50 g.

Q: What is tα/2,df for a 95% confidence interval of the population mean based on a sample of 15…

A: Solution: We have to find the t-critical value (tα/2) at the given significance level 1- 0.95=0.05…

Q: Use O The t Distribution Table to find the t2 value for an 80% confidence interval for the mean when…

A: Given Data : Sample Size, n = 14 confidence level , c = 80 % = 0.8

Q: Use the sample information x¯x¯ = 43, σ = 6, n = 13 to calculate the following confidence intervals…

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Q: If the population standard deviation is σ=10, how large a sample is necessary to have a standard…

A: σ=10   The standard error is given by SE = σn n = (σSE)2

Q: Find a 90% confidence interval for the difference between the population means for the two…

A: Given : For Sample 1 x̄1 = 3.11 n1 = 12

Q: Everything else being equal, a population with more variability yields a confidence interval that…

A: It is very useful in statistics . It has wide applications in all hypothesis testing problems .

Q: atn] Eight squirrels were found to have an average weight of 9.7 ounces with a sample standard…

A: The provided sample mean is Xˉ=9.7\bar X = 9.7 and the sample standard deviation is s=0.2s = 0.2.…

Q: Use The t Distribution Table to find the t/α2 value for a 98% confidence interval for the mean when…

A: Given that n = 17 Degrees of freedom = df = n - 1 = 17 - 1 = 16 t/α2 value for a 98% confidence…

Q: Find the critical value, t c,  used for a 90% confidence interval for the mean with a sample size of…

A: The confidence level is, 100 (1 – α) % = 90%. Hence, (1 – α) = 0.90, and the significance level is,…

Q: Which of the following is the minimum sample size necessary to construct a 99% confidence interval…

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Q: When conducting a t-test, you obtain the estimated standard error by dividing the sample standard…

A: Given the standard error is obtained by dividing the sample standard deviation by A. n-1B. nC. n-1D.…

Q: A reporter responsible for the food section of a magazine investigated the belief that grocery…

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Q: A sample of 150 brand A light bulbs showed a mean lifetime of 1392 hours and a standard deviation of…

A: Option C is correct

Q: To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19…

A:

Q: You are doing a class project for Stat 1, and do not have enough money to sample all mobile home…

A: At 95% confidence level, α=0.05 and z=1.96.

Q: A quality control expert at a pretzel factory took a random sample of 10 bags from a production run…

A:

Q: 530 males in the sample who gave a numeric response from 0 to 6, the mean was 2.51 and the standard…

A: Provided information is, n =530 x̅ =2.51 s =0.87 90% confidence interval can be calculated as:…

Q: A poll of 2500 people shows that 50% approve of a smoking ban in bars and restaurants in Kentucky.…

A: Given, n = 2500 p = 50% = 0.50 At 95% Confidence level, the value of Z is 1.96

Q: Suppose the variance of a sample is 7.3. Find the standard deviation. Round to two decimals.

A: Given : Variance , s2 = 7.3

Q: The amount of material used in making a custom sail for a sailboat is normally distributed with a…

A: Given σ=64, n=15  and  x¯=912

Q: Which distribution would be used to find the multiplier for this confidence interval? Select one: a.…

A: Given,n1=250X1=157n2=400X2=232

Q: A recent national survey found that high school students watched an average (mean) of 7.0 movies per…

A: 1.Null and alternative hypotheses:Null hypothesis:H0: µ = 7.0.That is, the average movies watched by…

Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

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Q: Use The t Distribution Table to find the t2 value for a 98% confidence interval for the mean when…

A: Obtain the degrees of freedom.   The degrees of freedom is obtained below as follows:   From the…

Q: In high school X, approximately 9 percent of the students saw a certain movie on opening night. From…

A: The standard deviation formula for testing the proportion is, σp^=p1-pn In the formula, p is…

Q: Find the critical value, for a 90% confidence when the sample size is 22

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Q: Use the sample information x¯x¯ = 36, σ = 5, n = 12 to calculate the following confidence intervals…

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Q: Develop a 95% confidence interval for the population slope if the following regression information…

A: Introduction: The 100 (1 – α) % confidence interval for the population partial slope coefficient, βi…

Q: se the given degree of confidence and sample data to construct a confidence interval for the…

A: We have given that  Sample size n= 30 Sample mean = 90 Standard deviation = 6.7 99% confidence…

Q: Suppose the variance of a sample is 5.7. Find the standard deviation. Round to two decimals.

A: According to the given information, we have Variance = 5.7

Q: A random sample of 24 army recruits has a mean height of 68 inches with a standard deviation of 2.3…

A: Given , n = 24 , mean = 68 , tandard deviation = 2.3