A sample of KHP, KHC&H4O4, weighing 4.070 g is titrated with NaOH and backtitratedwith HCI. NaOH required = 46.40 mL; HCI required = 5.35 mL. If each mL of HCl isequivalent (*) to 0.01600 g of Naz0, what volume of water or of 6.00 N NAOH must beadded to 500 mL of above NaOH to bring it to 0.5000N?5.%3D

Reaction: 2HCl + Na2O →2NaCl + H2O molar mass of Na2O = 62 g/mol mass of Na2O = 0.016 g moles of…

A sample of KHP, KHC&H4O4, weighing 4.070 g is titrated with NaOH and backtitrated with HCI. NaOH required = 46.40 mL; HCl required 5.35 mL. If each mL of HCl is equivalent (*) to 0.01600 g of Na20, what volume of water or of 6.00 N NAOH must be added to 500 mL of above NaOH to bring it to 0.5000N? %3D

A sample of KHP, KHC&H4O4, weighing 4.070 g is titrated with NaOH and backtitrated with HCI. NaOH required = 46.40 mL; HCl required 5.35 mL. If each mL of HCl is equivalent (*) to 0.01600 g of Na20, what volume of water or of 6.00 N NAOH must be added to 500 mL of above NaOH to bring it to 0.5000N? %3D

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter31: Introduction To Analytical Separations

Section: Chapter Questions

Problem 31.17QAP

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