A sample of vapor weighing 0. 200 g occupies a volume of 55 cc at 270C and 760 mmHg pressure. The critical pressure of the vapour is 47.7 atm, while the critical temperature is 288.50C. by use of the Berthelot equation, calculate the molecular weight of the vapour, and compare the result with that calculated by the ideal gas law.

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Answered: A sample of vapor weighing 0. 200 g…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter11: Liquids And Solids

Section: Chapter Questions

Problem 11.1QE

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A sample of vapor weighing 0. 200 g occupies a volume of 55 cc at 27⁰C and 760 mmHg pressure. The critical pressure of the vapour is 47.7 atm, while the critical temperature is 288.5⁰C. by use of the Berthelot equation, calculate the molecular weight of the vapour, and compare the result with that calculated by the ideal gas law.

Definition Definition Law that is the combined form of Boyle's Law, Charles's Law, and Avogadro's Law. This law is obeyed by all ideal gas. Boyle's Law states that pressure is inversely proportional to volume. Charles's Law states that volume is in direct relation to temperature. Avogadro's Law shows that volume is in direct relation to the number of moles in the gas. The mathematical equation for the ideal gas law equation has been formulated by taking all the equations into account: PV=nRT Where P = pressure of the ideal gas V = volume of the ideal gas n = amount of ideal gas measured in moles R = universal gas constant and its value is 8.314 J.K-1mol-1 T = temperature

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