A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite stays over a fixed point on the equator). Earth has mass M × 5.974 × 1024 kg and radius R × 6371 km. Assume G = 6.673 × 10¬11 m³ kg¬1 s-1. Use Kepler's Third Law to find the distance a from the center of Earth to the geosynchronous orbit. Compute the altitude h of the orbit above the Earth's surface. (Use decimal notation. Give your answers as a whole number.) a = km h = km

Physics for Scientists and Engineers: Foundations and Connections
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Chapter7: Gravity
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A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite
stays over a fixed point on the equator).
Earth has mass M × 5.974 × 1024 kg and radius R × 6371 km.
Assume G = 6.673 × 10¬11 m³ kg¬1 s-1.
Use Kepler's Third Law to find the distance a from the center of Earth to the geosynchronous orbit.
Compute the altitude h of the orbit above the Earth's surface.
(Use decimal notation. Give your answers as a whole number.)
a =
km
h =
km
Transcribed Image Text:A satellite orbiting above the equator of the earth is geosynchronous if the period is T = 24 hours (in this case, the satellite stays over a fixed point on the equator). Earth has mass M × 5.974 × 1024 kg and radius R × 6371 km. Assume G = 6.673 × 10¬11 m³ kg¬1 s-1. Use Kepler's Third Law to find the distance a from the center of Earth to the geosynchronous orbit. Compute the altitude h of the orbit above the Earth's surface. (Use decimal notation. Give your answers as a whole number.) a = km h = km
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