A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-).

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
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Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.3.20P: A plane Frame is restrained at joints A and D, as shown in the figure. Members AB and BCD are pin...
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A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have
magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A
and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical.
Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the
method of joints to determine the force in each member of the truss, and indicate whether they are in
tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
A
га
F₁
F3
B
S
LL
E
h
S
PAB =
117.1240
kip
× 0%
PAF = -102.7165
kip
? × 0%
PBC =
87.0837
kip
? × 0%
PBF =
26.3480
kip
× 0%
PCD =
87.0837
kip
? × 0%
PCF =
-61.610
kip
? × 0%
PDE=
117.1240
kip
? × 0%
PDF =
-26.3480
kip
100%
PEF=
-102.7165
kip
× 0%
Transcribed Image Text:A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A га F₁ F3 B S LL E h S PAB = 117.1240 kip × 0% PAF = -102.7165 kip ? × 0% PBC = 87.0837 kip ? × 0% PBF = 26.3480 kip × 0% PCD = 87.0837 kip ? × 0% PCF = -61.610 kip ? × 0% PDE= 117.1240 kip ? × 0% PDF = -26.3480 kip 100% PEF= -102.7165 kip × 0%
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