)A simple pendulum of length L is set to oscillate in simple harmonic motion. The bob gravitational potential energy is zero at its lowest vertical point. When the bob's height is at half its maximum, h = hmax /2, then its velocity is: (a) v = ghmax /2 ghmax (c) v = /2ghmax (d)v = 2/ghmax (b)v =

Classical Dynamics of Particles and Systems
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Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter12: Coupled Oscillations
Section: Chapter Questions
Problem 12.4P: Refer to the problem of the two coupled oscillators discussed in Section 12.2. Show that the total...
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10) A simple pendulum of length L is set to oscillate in simple harmonic motion. The bob gravitational
potential energy is zero at its lowest vertical point. When the bob's height is at half its maximum,
h = hmax /2, then its velocity is:
(a) v = /ghmax /2
(b) v = /ghmax
(c) v = /2ghmax
(d)v = 2/ghmax
%3D
Transcribed Image Text:10) A simple pendulum of length L is set to oscillate in simple harmonic motion. The bob gravitational potential energy is zero at its lowest vertical point. When the bob's height is at half its maximum, h = hmax /2, then its velocity is: (a) v = /ghmax /2 (b) v = /ghmax (c) v = /2ghmax (d)v = 2/ghmax %3D
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