A Single Angle Tension Member L 4"x4"x 10mm is connected to a gusset plate with 7/8" diameter bolts shown below. A36 Steel is used. The service loads are 30kips DL and 20 kips LL. Investigate this member for compliance with AlISC Specification. Assume that the effective net area is 90% of the computed net area. a) Use LRFD. 1. b) Use ASD. L3/2 x 3'/2 x /8 Section
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A: determining the factored load PuPu=1.2D+1LPu=1.2×75+40=130Kminimum gross area Ag…
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Q: The 10mm x 400mm plate has a steel grade of A36. The diameter of the bolt is 22 mm. The tension…
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Q: A Channel C6x13 is used as a tension member. The holes are for 5/8 inch in diameter of bolts. Using…
A: Data Given: Channel Section = C6×13Bolt Diameter = 58 inchFy = 36 ksiFu = 58 ksiAg = 3.81 in2U =…
Q: Question 8: (Consider tension member only; assume gusset plate design is adequate) A double-channel…
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A: The given figure is shown below:
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Q: A double-angle tension member, 2L 75 x 50 x 8 LLBB, of A36 steel with F= 250 MPa and Fy= 400 MPa, is…
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Q: A double-channel shape, 2C8 x 18.75 is used as a tension member. The channels are bolted to a 38 -…
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Q: nected to a 5⁄8-inch gusset plate as shown in the figure. Determine the maximum total service load…
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Q: 7.6-1 A double-angle shape, 2L6 X 6 × ½, is connected to a/s-inc shown in Figure P7.6-1. Determine…
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Q: 1. A double-channel shape, 2C8 18.75, is used as a tension member. The channels are bolted to a…
A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…
Q: A tension member is an L 150x90x8 connected to an 8-mm-thick gusset plate with 6-020 mm diameter,…
A: Answer We are given L 150 x 90 x 8 gusset plate thickness = 8 mm Fy = 248 Mpa Fu = 400 Mpa Bolt…
Q: 000 -P 38 63 63 38 252 63 63 63
A: A lap joint is the joint between two bits of metal wherein the edges or closures are covered and…
Q: A C8 x 18.75 is to be used as a tension member. The channel is bolted to a 3⁄8-inch gusset plate…
A: Solution Given Data C8 x 18.75
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A: LFRD stands for Load Resistance Factor Design, it is a method of designing concrete and steel…
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Q: A C12x30 is connected with 1-inch diameter bolts in each flange (see below). The steel is A572…
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Q: A W10x45 with two lines of (3/4)in diameters bolts in each flange using A572 grade 50 steel is used…
A: Answer We are given bolt diameter = 3/4 in W 10 x 45 A 572 grade steel To determine the LRFD design…
Q: A Channel Cóx13 is used as a tension member. The holes are for 5/8 inch in diameter of bolts. Using…
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Q: Select a single-angle tension member of A36 (Fy=36ksi and Fu=58ksi) steel to resist the following…
A: The yield strength is Fy=36 ksi. The ultimate strength is Fu=58 ksi. The dead load is D=50 kips. The…
Q: A tension member with a length of 6 feet must resist a service dead load of 22 kips and a service…
A: Rectangular c/sDL = Dead load = 22 kipsLL = Live load = 55 kipsL = Length of member = 6 ft = 6×12 =…
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A: Solution: The Calculation for ASD method:
Q: Fy= 50 Ksi, Fu= 65ksi Select the lightest W10 section available to support working tensile loads of…
A: Given : Fy= 50 Ksi, Fu= 65ksi Select the lightest W10 section available to support working tensile…
Q: 1. A double-channel shape, 2C8 18.75, is used as a tension member. The channels are bolted to a…
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Q: A double-angle shape, 2-L6 x 6 x %½, is connected to a %-inch gusset plate as shown in the figure.…
A: We will solve this question in step no 2
Q: 2. Determine the design strength P of an A992 W18x50 connected by bolts on plates on both flanges as…
A: The values are as follows,w18×50A992Ag=14.7in2fy=50ksid=17.99infu=65ksilf=0.57inTo determine the…
Q: An ASTM A992 WT6-section is to be used to resist a dead load of 310 kips and a live load of 425 kips…
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Q: Determine the lightest W 12 (A36) section suitable for a 8 m long W-shape member to carry an axial…
A: Solution Given: A36 steel fy = 36 ksi = 250 MPa fu = 500 MPa db = 20 mm P = 1900 kN
Q: 2. A 1/2X5 plate of A36 steel is used as a tension member. It is connected to a gusset plate with…
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Q: 1. A double-channel shape, 2C8 18.75, is used as a tension member. The channels are bolted to a…
A: The given figure is shown below:
Q: A W10x45 tension member with no holes is subjected to service dead load of 200+(37*10)kN , a service…
A: Solution: Given Data: W10×45(Tension member)A992 Grade 50 steelFy=50 ksiCb=1.0Dead load…
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A: LRFD Method LRFD is known as Load and Resistance Factor Design . It is the important factor which is…
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Q: A C8 x 11.5 is connected to a gusset plate with 7/8 inch diameter bolts as shown in Figure P3.2-3.…
A: Solution For grade 50 A5672Fy =50 ksiFu=65 ksit=0.75Ag=3.37 in2.tw=0.22 in
Q: 2. A single-angle tension member, an L3 x3 x3/8, is connected to a gusset plate with 22mm- diameter…
A: Given data L 312x312x38 diameter of bolt = 22 mm A (36 steel) Service Dead load = 155 KN Service…
Q: Problem 3 The W12 x 53 tension member shown in Figure 5 has two rows of three 25-mm-diameter A325N…
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Q: A built-up section consists of two channels (C 300 x 37) and two steel plates 12.52 x 300mm bolted…
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Q: Problem 3 The W12 x 53 tension member shown in Figure 5 has two rows of three 25-mm-diameter A325N…
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Q: 3-27. AW18X 40 consisting of A992 steel and having two lines of 1-in Ø bolts in each flange. There…
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Q: The tension member shown is an angle L150 x 90 x 10, of A36 steel, with Fy= 250 MPa and F,= 400 MPa,…
A: Given : L150X90X10 A36 steel : Fy = 250 MPa, Fu = 400 MPa DL = 150kN, LL = 150 kN Bolts are 20 mm…
Q: A WT 8x13 of A992 steel is used as a tension member. The connection is with 7/8-in. diameter bolts…
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Q: A double angle 2-L152x152x15.9 is connected to a 16mm gusset plate as shown. The bolts are M22,…
A: Given data: Double angle of 152*152*15.9 Thickness of gusset plate=16 mm Fy=345 MPa for angle…
Q: An ASTM A992 WT6-section is to be used to resist a dead load of 310 kips and a live load of 425 kips…
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- A 2L 3 x 2 x ¼ LLBB tension double angle, A36 steel is subjected to a dead load of 12 kips and a live load of 36 kips. It is attached to a gusset plate with a line of 3/4-inch diameter bolts through the long legs. Does this member have enough stamina? Assume Ae= 0.85 in. Use LRFD.A channel shape, C8 × 18.75, is used as a tension member. The channels are boltedto a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs?A channel shape, C8 × 18.75, is used as a tension member. The channels are bolted to a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs? What is the ult. capacity of the gusset plate in kips, if block shear governs? What is the effective net area of the channel section, in square millimeters?
- The 10mm x 400mm plate has a steel grade of A36. The diameter of the bolt is 22 mm. The tensionmember shown has a length of 6 m. If the said tension member is carrying a tensile dead load of 698kN and a tension live load of 668 kN, determine the following:a. Effective areab. Is the member satisfactory? Use LRFD and ASD.A double-channel shape, 2C8 x 18.75 is used as a tension member. The channels are bolted to a ⅜ - inch gusset plate with ⅞ - inch diameter bolts. The tension member is A572 grade 50 steel and the gusset plate is A36. If LRFD is used, how much factored tensile load can be applied? Consider all limit states.A single-angle tension member, an L3 1⁄2 × 3 1⁄2 × 3⁄8, is connected to a gusset plate with 7⁄8-inch-diameter bolts as shown in the figure. A36 steel is used. Fy = 50 ksi, Fu = 58 ksi, E = 29000 ksi. Ag = 2.50 in^2. Assume that the effective net area is 85% of the computed net area.
- A tension member is an. L150x90x8 connected to an 8-mm thick gusset plate with 6-20mm diameter, A325 bearing type bolts with threads in shear planes. All members are A36 steel with Fu = 400 Mpa. Deformation at bolt hole is a design consideration. a. Calculate the service deadload that can be supported based on bolt shear by LRFD using factor phi of 0.75. If the ratio of live load to dead load is 2.0. (ANS 119)b. Calculate the service dead load that can be supported based on bearing strength of the tension member by LRFD with phi = 0.75. If the ratio of live load and dead load is 2.0 c. Calculate the service dead load that can be supported based on bearing strength of the gusset plate by LRFD with phi = 0.75. If the ratio of live load and dead load is 2.0A 1 ⁄2 × 5-inch plate of A588 steel is used as a tension member. It is connected to a gusset plate with four 5 ⁄8-inch-diameter bolts as shown in Figure 1. Assume that the effective net area Ae equals the actual net area An. (a) Calculate the design strength for LRFD? (b) Calculate the allowable strength for ASD?Select the lightest avaliable W-10 section to support the axial loads PD= 90 kips, PL= 120 kips, Lc= 15ft, Fy= 50 ksi Answer is W10 x 45 LRFD and ASD using the colum table in Aisc manual especially part 4 please do a step by step solution I have many problems to work on and I want to understand the entire process.
- 1. An unsymmetrical flexural member consists of a 70 × 600 top flange, a 70 x 400 bottom flange, and a 12 × 180 web. a, Determine the Section Modulus. b. Determine the distance from the bottom of the shape to the horizontal plastic neutral axis. ( Take note: Bottom Distance i need, not the top distance) c. If A572 Grade 50 steel is used, what is the plastic moment MPy for the horizontal plastic neutral axis?A single angle tension member, L 4 x 4 x 3/8 in. made from A36 steel is connected to a gusset plate with 5/8 in. diameter bolts, as shown in Figure below. The service loads are 35 kips dead load and 15 kips live load. Determine the adequacy of this member using AISC specification. Assume that the effective net area is 85% of the computed net area.A W18 × 119 is used as a compression member with one end fixed and the other end fixed against rotation but free to translate. The length is 12 feet. If A992 steel is used, what is the available compressive strength? a. Use AISC Equation, compute both the design strength for LRFD and the allowable strength for ASD.b. Use Table 4-22 from Part 4 of the Manual. Compute both the design strength for LRFD and the allowable strength for ASD.