A slightly simplified view of the arm has the hinge at the elbow, the bicep attaching to the bone 2.50 cm from the 'hinge' and a mass supported in the hand 32.0 cm from the 'hinge'. If the mass of the forearm is 2.60 kg and its center of mass is 12.0 cm from the Biceps 'hinge', how many Newtons of force from the bicep would be required to hold up 32 сm a weight of 98.0 N? 2.5 cm

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter14: Static Equilibrium, Elasticity, And Fracture
Section: Chapter Questions
Problem 31PQ: A wooden door 2.1 m high and 0.90 m wide is hung by two hinges 1.8 m apart. The lower hinge is 15 cm...
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A slightly simplified view of the arm has the hinge at the elbow, the bicep attaching to the bone 2.50
cm from the 'hinge' and a mass supported in the hand 32.0 cm from the 'hinge'.
If the mass of the forearm is 2.60 kg and its center of mass is 12.0 cm from the
Biceps
'hinge', how many Newtons of force from the bicep would be required to hold up
32 em
a weight of 98.0 N?
25 cm
Transcribed Image Text:A slightly simplified view of the arm has the hinge at the elbow, the bicep attaching to the bone 2.50 cm from the 'hinge' and a mass supported in the hand 32.0 cm from the 'hinge'. If the mass of the forearm is 2.60 kg and its center of mass is 12.0 cm from the Biceps 'hinge', how many Newtons of force from the bicep would be required to hold up 32 em a weight of 98.0 N? 25 cm
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