A small box with a mass of 6.61 kg is being swung around on the end of a string which has a length, L = 1.52 m. The box has a tangential velocity of 3.20 m/s and is moving on a level, horizontal surface which has a co-efficient of kinetic friction of 0.345 and a co-efficient of static friction of 0.397. Part A What is the centripetal acceleration of the box? ac = 6.74 m/s² Submit ✓ Correct Part B Previous Answers What is the force of tension in the string? Fr= Part C [-] ΑΣΦ Submit Request Answer How much energy is lost due to friction in one rotation? ► View Available Hint(s) ΠΙ ΑΣΦ ? E = 145.1 ? N J P Pearson side view L top "bird's eve" view TLL Vy
A small box with a mass of 6.61 kg is being swung around on the end of a string which has a length, L = 1.52 m. The box has a tangential velocity of 3.20 m/s and is moving on a level, horizontal surface which has a co-efficient of kinetic friction of 0.345 and a co-efficient of static friction of 0.397. Part A What is the centripetal acceleration of the box? ac = 6.74 m/s² Submit ✓ Correct Part B Previous Answers What is the force of tension in the string? Fr= Part C [-] ΑΣΦ Submit Request Answer How much energy is lost due to friction in one rotation? ► View Available Hint(s) ΠΙ ΑΣΦ ? E = 145.1 ? N J P Pearson side view L top "bird's eve" view TLL Vy
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section: Chapter Questions
Problem 6OQ: A pendulum consists of a small object called a bob hanging from a light cord of fixed length, with...
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A small box with a mass of 6.61 kgkg is being swung around on the end of a string which has a length, L=L=1.52 mm . The box has a tangential velocity of 3.20 m/sm/s and is moving on a level, horizontal surface which has a co-efficient of kinetic friction of 0.345 and a co-efficient of static friction of 0.397.
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