Question

Asked Feb 13, 2020

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A small bucket contains 4 red balls, 8 green balls, and 12 blue balls. Three balls are drawn at random, one after the other, without replacement.

What is the probability of the sequence red, green, blue?

What is the probability that all three balls will be the same color?

Step 1

It is given that the bucket consists of 4 red balls, 8 green balls and 12 blue balls.

The probability that the first ball is red is, 4/24.

The probability that the second ball is green is, 8/23.

The probability that the third ball is blue is, 12/22.

The probability that the first ball obtained is red and second is green and the third is blue is,

4/24×8/23×12/22 = **0.0316.**

Step 2

**The probability that all three balls are of the same color:**

All three balls are red or all three balls are green or all three balls are blue.

If all three balls are red, then the probability that the first ball is red is, 4/24.

The probability that the second ball is red is, 3/23.

The probability that the third ball is red is, 2/22.

If all three balls are green, then the probability that the first ball ...

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