A small mass charged sphere ( q= 3 µ C) is attached by an insulating string to the surface of a very large conductor with a surface charge density of o = 37.6 µC. Given that the string makes an angle with the surface equal to 30 degrees, find the tension ( in N) in the string. use ɛO = 8.8542x10-12 F · m-1. String Select one: A. 38.22 B. 14.71 C. 12.74 D. 25.48 E. 50.34 + + + + +

A small mass charged sphere ( q= 3 µ C) is attached by an insulating string to the surface of a very large conductor with a surface charge density of o = 37.6 µC. Given that the string makes an angle with the surface equal to 30 degrees, find the tension ( in N) in the string. use ɛO = 8.8542x10-12 F · m-1. String Select one: A. 38.22 B. 14.71 C. 12.74 D. 25.48 E. 50.34 + + + + +

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 68PQ: Examine the summary on page 780. Why are conductors and charged sources with linear symmetry,...

See similar textbooks

Similar questions

The field due to two parallel plates, the left with a negative surface charge density of −6.0 C/m2 whilethe sheet on the right has a positive surface charge density of +9.0 C/m2is given below. Suppose the plates were spaced 0.0020 m apart. We found that, using Gauss’s law that, independent of this distance, • In I the net field points to the left and has magnitude |Enet| = 1.69 × 1011 N/C.• In region II, between the plates, the field has magnitude 8.47×1011 N/C and points to the left• In III it points to the right and has magnitude |Enet| = 1.69 × 1011 N/C.
Find the electnc field intensity at the point P(8,4,4) due to a uniform line charge lying along the x-axis and extending from (6) to + (-6)?
I've tried to solve for the E-field, but i cnat seem to get it right
Show electrostatically that the electric field vector can be written as the gradient of a scalar.
A metal ball (electrically conductive) with a radius of R = 10cm was placed in a vacuum and charged with a positive charge Q = 20μC. Using Gauss's law, determine the function describing the value of the radial component of the electric field intensity vector depending on the distance from the center of the spherical field for distances greater than or less than the radius of the sphere. Sketch the course of this function describing on the XY axes the characteristic values for the distance equal to the radius of the sphere at the center of the sphere.
A semicircle ofradius a is in the first and secondquadrants, with the center of curvatureat the origin. Positive charge+Q is distributed uniformly aroundthe left half of the semicircle, andnegative charge -Q is distributeduniformly around the right half ofthe semicircle (Fig. ). Whatare the magnitude and direction of the net electric field at the originproduced by this distribution of charge?
Find all the bound charges and the total charge of a dielectric sphere of radius a carrying polarization P = rr ̂ ?
The charge per unit length on the thin rod shown below is λ . What is the electric field at the point P? (Hint: Solve this problem by first considering the electric field dE at P due to a small segment dx of the rod, which contains charge dq = λdx . Then find the net field by integrating dE over the length of the rod.)
As shown in Figure, a particle of charge +Q produces an electric field of magnitude Epart at point P, atdistance R from the particle. As in figure b, that same amount of charge is spread uniformly along a circulararc that has radius R and subtends an angle ?. The charge on the arc produces an electric field of magnitudeEarc at its center of curvature P. For what value of ? does Earc = 0.50 Epart ?
A point charge q= 4.7 uC is placed at each corner of an equilateral triangle with sides 210mm in length. (a) What is the magnitude of the electric field at the midpoint of any of the three sides of the triangle? b) is the magnitude of the elctric field at the ceneter of the triangle less than, greater than or the same as the magnitufr at midpoint of a side? Draw a skwtch with all apprpoate vectors.
For a Certain surface ‘S’, if polarization vector ‘P’ is equal to 2× 10-16 C/m2is inclined at an angle of 60 degrees normal to that surface what is the value of bound surface charge density ‘σ’ of that surface?
The charge per unit length on the thin rod shownbelow is λ . What is the electric field at the point P? (Hint:Solve this problem by first considering the electric fieldd E→ at P due to a small segment dx of the rod, whichcontains charge dq = λdx . Then find the net field byintegrating d E→ over the length of the rod.)