answer quickly A small object faces the convex spherical glass window of a small water tank. The radius ofcurvature of the window is 5cm. The inner back side of the tank is a plane mirror, 20cm fromthe window. The index of refraction of water is 1.33. Neglect any refraction due to the thinglass window itself. If the object is 30cm outside the glass window, determine:a) The position of the final image. Specify the nature of the final image. Find the overallmagnification of the object.b) Solve the same problem for the case of the mirror back side of the tank being 60cm fromthe window.c) How would the answers to part a) change if the mirror is 40.7cm from the window? Beas specific as you can.

Given:- The object distance is u = -30 cm The radius of curvature of the glass R = 5 cm the…

Answered: A small object faces the convex…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter26: Image Formation By Mirrors And Lenses

Section: Chapter Questions

Problem 7P

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Similar questions

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Figure P38.43 shows a concave meniscus lens. If |r1| = 8.50 cm and |r2| = 6.50 cm, find the focal length and determine whether the lens is converging or diverging. The lens is made of glass with index of refraction n = 1.55. CHECK and THINK: How do your answers change if the object is placed on the right side of the lens? FIGURE P38.43
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A small bead 2.75 [mm] in size is located 21.0 [cm] from the center of aconcave spherical mirror with radius of curvature of 16.0 [cm] along the optical axis.Consider the system in the previous item, but this time the concave sphericalmirror is replaced by a convex spherical mirror of the same radius of curvature. What is thelocation, height, and orientation of the image of the bead?
A spherical convex mirror has a radius of curvature with a magnitude of 40.0 cm. Determine the position of the virtual image and the magnification for object distances of (a) 30.0 cm and (b) 60.0 cm. (c) Are the images upright or inverted?
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