  A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with orange light of wavelength 620 nm, one sees that a distance of 3.60 cm separates two bright fringes that are 3 orders apart. By how much does the film differ in thickness over this distance?

Question

A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with orange light of wavelength 620 nm, one sees that a distance of 3.60 cm separates two bright fringes that are 3 orders apart. By how much does the film differ in thickness over this distance?

Step 1

Given: wavelength = 620 nm

m = 3 order

n = 1.33

distance, d = 3.60 cm = 0.036 m

Find: How much does the film differ in thickness over this distance

Step 2

Let "t" be the thickness of the film as:

Step 3

The condition for the b...

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Physics 