A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with orange light of wavelength 620 nm, one sees that a distance of 3.60 cm separates two bright fringes that are 3 orders apart. By how much does the film differ in thickness over this distance?
A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with orange light of wavelength 620 nm, one sees that a distance of 3.60 cm separates two bright fringes that are 3 orders apart. By how much does the film differ in thickness over this distance?
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Wave Optics
Section: Chapter Questions
Problem 10OQ: A Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a...
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A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with orange light of wavelength 620 nm, one sees that a distance of 3.60 cm separates two bright fringes that are 3 orders apart. By how much does the film differ in thickness over this distance?
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