A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with the orange light of wavelength 630 nm, one sees that a distance of 2.60 cm separates two bright fringes that are 4 orders apart. By how much does the film differ in thickness over this distance? in mico meters.

University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter4: Diffraction
Section: Chapter Questions
Problem 92AP: A single slit of width 2100 nm is illuminated normally by a wave of wavelength 632.8 nm. Find the...
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A soap film (n = 1.33) is formed in a loop of wire
that is mounted vertically is not exactly uniform in
thickness because of its weight, but wedge-shaped
in cross section. When the film is illuminated with
the orange light of wavelength 630 nm, one sees
that a distance of 2.60 cm separates two bright
fringes that are 4 orders apart. By how much does
the film differ in thickness over this distance? in
%3D
mico meters.
Transcribed Image Text:A soap film (n = 1.33) is formed in a loop of wire that is mounted vertically is not exactly uniform in thickness because of its weight, but wedge-shaped in cross section. When the film is illuminated with the orange light of wavelength 630 nm, one sees that a distance of 2.60 cm separates two bright fringes that are 4 orders apart. By how much does the film differ in thickness over this distance? in %3D mico meters.
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