A solution is 1 X 10-4 M in NaF, Na2S, and Na3PO4. What would be the order ofprecipitation as a source of Pb?* is added gradually to the solution? The relevant Ksp values are Ksp,(PBF2) = 4 X10*, Ksp, (PbS)= 7 X 10-2º, and Ksp, [Pb3(PO4)2] = 1 X10-54

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A solution is 1 X 104 M in NaF, Na2S, and Na3PO4. What would be the order of precipitation as a source of Pb²* is added gradually to the solution? The relevant Ksp values are Ksp. (PBF2) = 4 X10*, Ksp. (PbS)= 7 X 10-2º, and Ksp. [Pb3(PO4)2] = 1 X10-54 %3D

A solution is 1 X 104 M in NaF, Na2S, and Na3PO4. What would be the order of precipitation as a source of Pb²* is added gradually to the solution? The relevant Ksp values are Ksp. (PBF2) = 4 X10*, Ksp. (PbS)= 7 X 10-2º, and Ksp. [Pb3(PO4)2] = 1 X10-54 %3D

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter15: Equilibria Of Other Reaction Classes

Section: Chapter Questions

Problem 11E: The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities...

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Question

A solution is 1 X 10-4 M in NaF, Na2S, and Na3PO4. What would be the order of
precipitation as a source of Pb?* is added gradually to the solution? The relevant Ksp values are Ksp,
(PBF2) = 4 X10*, Ksp, (PbS)= 7 X 10-2º, and Ksp, [Pb3(PO4)2] = 1 X10-54

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