A solution is made by mixing 96. g of acetyl bromide (CH3COBR) and 130. g of benzene (C,H6). Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 2 significant digits.

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Chapter1: Matter, Measurements, And Calculations
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Problem 1.126E
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A solution is made by mixing 96. g of acetyl bromide (CH3COBR) and 130. g of benzene (C,H6).
Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 2 significant digits.
Transcribed Image Text:A solution is made by mixing 96. g of acetyl bromide (CH3COBR) and 130. g of benzene (C,H6). Calculate the mole fraction of acetyl bromide in this solution. Round your answer to 2 significant digits.
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