A solution is made from CaCl, and MgCl2 so that [Ca*²] = 0.00050 M, [Mg*²] = 0.00050 M. A 0.05M solution of Na2Cr207 is added. Answer the following questions. Note: Ksp(CaCr2O7) = 4.8*107 Ksp(MgCr2O7) = 7.6*10-8 Which salt will be the first to precipitate? Na2Cr207 CaCr2O7 CaCl2
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- If we are given that the Ksp for BiI3 is 8.1 x 10-19, then what is the solubility in water, 0.30 M NaI, and 0.03 M Bi+3? ( well explain allpoint of question with deep explaination. )Ksp of Cd(IO₃)₂ (462.22 g/mol) is 2.3 × 10⁻⁸. How much dissolved Cd(IO₃)₂ is in a 750.0 mL Cd(IO₃)₂ clear solution? Choices: 621.1 mg 52.57 mg 985.9 mg None of theseA Na2S2O3 titrant was standardized by taking 50.0 mL of 6.7863 x 10-3 M standard KIO3 solution, acidifying, and adding KI crystals. Titration of this solution required 9.80mL to reach the starch endpoint. What is the concentration of the Na2S2O3 titrant?
- When CaF2 is dissolved in water to reach saturation, the concentration of Ca2+ = 4.2 x 10-4 M. (a) Calculate Ksp for this compound. (b) The Ksp for Ag2CrO4 is 1.1 x 10-12 at 25oC. Calculate the solubility of this compound in grams per litre.A 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2O to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H+ = 3 I2 + 6 K+ + 3 H2O C6H8O6 + I2 = C6H6O6 + 2I- + 2H+ A 67.77 % B 33.89 % C 22.59 % D 3.39 %An unknown sample of Cu2+gave an absorbance of 0.262. Then 1.00 mL of solution containing 100 ppm (ug/mL)Cu2+was mixed with 95.0 mL of the unknown and the mixture was diluted to 100 mL in a volumetric flask with deionized water. The absorbanceof the new solution was 0.500. a.Denoting the initial unknown concentrationas [Cu2+]i,write an expression for the final concentrationafter dilution [Cu2+] b.Find [Cu2+]in the unknown.
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