A solution is prepared by adding 0.17 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.7 M NH3. Calculate Ni (NH3 ),+ and Ni²+ in this solution. 2+ Koverall for Ni (NH3), is 5.5 × 10°. That is, Ni (NH3)6 2+ 5.5 x 108 = [Ni²+] [NH31* for the overall reaction 2+ Ni?+ (aq) + 6NH3 (ag) → Ni (NH3)6* (aq) [Ni (NHL),*] =[ [N**] - M. M =

Chemistry for Engineering Students
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Chapter12: Chemical Equilibrium
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Problem 12.54PAE
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[Ni (NH,),*]:
[N*]
A solution is prepared by adding 0.17 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.7 M NH3. Calculate
and
in this solution.
2+
Koverall for Ni (NH3)6
is 5.5 × 10°. That is,
Ni (NH3)6
2+
5.5 x 108 =
Ni2+
for the overall reaction
Ni2+ (ag) + 6NH3 (aq) = Ni (NH3)6* (aq)
2+
2+
3)6
M
=
[N**] - [
M
Transcribed Image Text:[Ni (NH,),*]: [N*] A solution is prepared by adding 0.17 mole of Ni(NH3)6 Cl2 to 0.50 L of 3.7 M NH3. Calculate and in this solution. 2+ Koverall for Ni (NH3)6 is 5.5 × 10°. That is, Ni (NH3)6 2+ 5.5 x 108 = Ni2+ for the overall reaction Ni2+ (ag) + 6NH3 (aq) = Ni (NH3)6* (aq) 2+ 2+ 3)6 M = [N**] - [ M
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