A solution is prepared by adding 0.19 mole of Ni(NH3), Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),*| and Ni?+ for Ni (NH3),+ is 5.5 x 10$. That is, in this solution. Koverall Ni(NH,), [N²-] INH" 5.5 x 108 = for the overall reaction Ni2+ (ag) + 6NH3 (aq) = Ni(NH3),* (ag) [NI(NH,),]-C 2+ M [N*]-C M 3 item attempts remaining Submit Answer Try Another Version

General Chemistry - Standalone book (MindTap Course List)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter21: Chemistry Of The Main-group Elements
Section: Chapter Questions
Problem 21.199QP
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[References]
A solution is prepared by adding 0.19 mole of Ni(NH3). Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),* and Ni²+
in this solution. Koverall
for Ni (NH3)+ is 5.5 x 10°. That is,
[NI(NH,),
2+
5.5 x 108 =
for the overall reaction
Ni?+ (aq) + 6NH3 (aq) = Ni(NH3)6* (ag)
%3D
[N*] =[
M
Try Another Version
3 item attempts remaining
Submit Answer
4:44 PM
3/30/20
search
远
Transcribed Image Text:w.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take [References] A solution is prepared by adding 0.19 mole of Ni(NH3). Cl2 to 0.50 L of 3.9 M NH3. Calculate Ni (NH3),* and Ni²+ in this solution. Koverall for Ni (NH3)+ is 5.5 x 10°. That is, [NI(NH,), 2+ 5.5 x 108 = for the overall reaction Ni?+ (aq) + 6NH3 (aq) = Ni(NH3)6* (ag) %3D [N*] =[ M Try Another Version 3 item attempts remaining Submit Answer 4:44 PM 3/30/20 search 远
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