A solution of an unknown carbohydrate gave the following optical readings when analyzed by a polarimeter +3.24, +3.15, +3.30, +3.20, 3.21, +3.19, +3.17, +3.23, +3.20, +3.25. 1. (a) Calculate the sample mean.
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- Describe the preparation of the following solutions include all mathematic calculations and equipment of the laboratory needed A.500 mm of a solution of KNO 1.50 M B. 150 g of a solution 5.0% of NaC2H3O2 C. 500 mm of a solution of NaOH 0.50 M from a solution of NaOH 6.0 MPropanamide and methyl acetate have about the same molar mass, both are quite soluble in water, and yet the boiling point of propanamide is 486 K, whereas that of methyl acetate is 330 K. Explain.The main constituents in vinegar are water and ethanoic acid (CH3COOH). In order to determine the concentration of acid in homemade vinegar, a student titrated 25 cm3 of 001 M NaOH against the vinegar. The equation for the reaction is: CH3COOH(aq) + NaOH(aq) ® CH3COONa(aq) + H2O(l) The following titration results were obtained: Burette readings (cm3) Rough 1 2 Final burette reading 20.10 38.90 31.40 Initial burette reading 0.10 20.00 12.50 Volume of vinegar used 20.00 18.90 18.90 (a) What volume of vinegar should be used in the calculation? (b) What is the mole ratio of NaOH:CH3COOH? (c) Calculate the number of moles of alkali in 25 cm3 of NaOH solution used. (d) How many moles of acid were used in the titration? (e) Calculate the…
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