A solution of rubbing alcohol is 80.0 %% (v/v) isopropanol in water. How many milliliters of isopropanol are in a 92.4 mLmL sample of the rubbing alcohol solution? How many liters of a 3.90 MM K2SO4K2SO4 solution are needed to provide 73.3 gg of K2SO4K2SO4(molar mass 174.01 g/molg/mol)? Recall that MM is equivalent to mol/Lmol/L.

Introductory Chemistry For Today
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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.65E
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A solution of rubbing alcohol is 80.0 %% (v/v) isopropanol in water. How many milliliters of isopropanol are in a 92.4 mLmL sample of the rubbing alcohol solution?

How many liters of a 3.90 MM K2SO4K2SO4 solution are needed to provide 73.3 gg of K2SO4K2SO4(molar mass 174.01 g/molg/mol)? Recall that MM is equivalent to mol/Lmol/L.

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