A solution was prepared by dissolving 118.9 mg of K2C12O7 in 1.000 L of water. A 10.00 mL aliquot was transferred to a 100.0 mL volumetric flask and diluted to the mark. The dilute solution had an absorbance of 0.206 at 400 nm, in a 1.00 cm cell. a. What is the concentration of the dilute solution in ppm? b. Using Beer's Law equation, calculate the molar absorptivity of K2Cr2O7
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- (a) Standard Ag1 solution was prepared by dissolving 1.224 3 g of dry AgNO3 (FM 169.87) in water in a 500.0-mL volumetric flask. A dilution was made by delivering 25.00 mL of solution with a pipet to a second 500.0-mL volumetric flask and diluting to the mark. Find the concentration of Ag1 in the dilute solution. (b) A 25.00-mL aliquot of unknown containing Cl2 was titrated with the dilute Ag1 solution, and the equivalence point was reached when 37.38 mL of Ag1 solution had been delivered. Find the concentration of Cl2 in the unknown.0.3785 g of a sample containing calcium was analyzed by dissolving it in 250 mL and titrating a 25 mL aliquot. This consumed 18.75 mL of 0.0184 M EDTA solution. Express the calcium content in:a) ppm CaO b) ppm CaCO3 c) ppm CaC12d) ppm Ca3(P04)2Chemistry The most abundant type of mammalian antibody circulating in the blood stream is IgG. A solution prepared from 0.798 g of a particular IgG in 250 mL of water shows an absorbance of 0.578 at 275 nm in a 1.00 cm cell. If the molar absorptivity of the IgG is 6.49 × 104 M–1 cm–1 at 275 nm, what is the molar mass of the IgG? Present your numerical answer in kg·mol-1 to 3 significant figures .
- A 0.53 g sample containing KBr (MW=119) is dissolved in 50 mL of distilled water. Titrating with 0.04614 N AgNO3 requires 28.5 mL to reach the endpoint. Calculate the %w/w KBr in the sample. (Round-off your answer to 2-decimal places) Answer = ____%Five white, 500-mg uncoated ascorbic acid (AA) tablets with an average weight of 0.6152-g were pulverized in a mortar. A sample of the powdered ascorbic acid weighing 0.4700-g was placed in an iodine flask and was dissolved in 50-mL H2SO4 then 5-g of KBr was added to the resulting solution. The solution was titrated with 47.81-mL of 0.09640 N STD. KBrO3 to reach a faint yellow endpoint then 3-g KI and 5-mL Starch TS. The blue color solution is then titrated with 2.73-mL of 0.09123 N STD. Na2S2O3 to reach the disappearance of the blue iodostarch complex. MW: KBrO3 = 167.0 ; KIO3 = 214.0 ; Na2S2O3 = 158.11 ; C6H8O6 = 176.12 Compute the milligrams of pure AA per tablet from the assay. 293.3 mg 502.5 mg None of the choices 383.9 mgA mixture containing only KCl and NaBr is analyzed by the Mohr Method. A 0.3172-g sample is dissolved in 50 mL water and titrated to the Ag2CrO4 endpoint, requiring 36.85 mL of 0.1120 M AgNO3. A blank titration requires 0.71 mL of titrant to reach the same endpoint. Report the % (w/w) KCl and NaBr in the sample. [Answer should be 82.41 % (w /w)]
- A 0. 6875 g rock sample containing an unknown amount of Ca was dissolved in HCl and diluted to 200.00 mL. Aliquots of 20 mL of this unknown solution were added to different volumes of a 8.02?g/mL Ca standard solution and diluted to 100.00 mL. A plot of absorbance vs. concentration of standard gives a trendline of with slope of 1746. 7. The solution of 20 mL of unknown diluted to 100 mL and without any standard gave an absorbance of 215.8. Find the weight percent of Ca in the rock.An unknown sample of Cu2+ gave an absorbance of 0.475 in an atomic absorption analysis. Then 5.00 mL of solution containing 75.0 ppm (= µg/mL) Cu2+ was mixed with 45.0 mL of unknown, and the mixture was diluted to 500.0 mL in a volumetric flask. a) Write an expression for the final concentration after dilution. b) Calculate the final concentration of the added standard. c) The absorbance of the new solution was 0.987. Find the initial concentration of Cu2+ in the unknown sampleThe nitrite in a series of standard solutions (mg/L, n = 5) are converted to azo dye and the slope of the calibration curve is 2.0 ppm1. A 10.00-mL mineral water sample is treated in the same way as standards and diluted to a final volume of 100.00-mL. It gives an absorbance of 0.80. The absorbance of blank solution under the same conditions is 0.10. Calculate ppm (mg/L) of NO2 (46 g/mol) and the molarity of NANO2 (69 g/mol) in the original sample
- Hw.22. A 1 mL aliquot of standard KMnO4 solution A (4.0 ppm) gets added to 10 mL of unknown solution B. This 11 mL solution then has an absorbance of 0.312. The absorbance of unknown KMnO4 solution B is 0.326. Calculate the concentration of solution B in ppm. Use simultaneous equations.50.00 mL of a water sample is diluted with 150.00mL deionized water. The diluted sample has a lead content of 17.8 ppb. What us the led content (in ppb) of the original sample?A 0.2653 g of pure potassium dichromate was dissolved in 15 mL of 1.5 M sulfuric acid and transferred to a 250.0 mL volumetric flask and diluted to the mark with distilled water. A 25.0 mL aliquot of this solution was transferred to another 250.0 mL volumetric flask and diluted to the mark with distilled water and this solution has an absorbance 0f 0.387 in a 2.00 cm cell. Calculate the molar absorptivity of potassium dichromate.