A spring of constant k=8 N/m hanging from the ceiling is placed at its lower end with an object of 1N which makes it remain in equilibrium, then the weight is pulled 0.8 m above the equilibrium position and is released with no initial velocity, no damping force acts on the system. If x(t) represents the displacement of the weight in meters, from the equilibrium point and taking upwards as the positive direction, an equation that describes the position of the weight as a function of time in seconds (gravity 9.8m/s^2) O a) (t) = 0.8 cos(t/78.4) O b) z(t) = 0.4 sen(t/78.4) %3D O c) z(t) = 0.8 (eVT84 +e tv784) ot/78.4 %3D O d) z(t) = 0.4 (ev784 + e -t/78.4
A spring of constant k=8 N/m hanging from the ceiling is placed at its lower end with an object of 1N which makes it remain in equilibrium, then the weight is pulled 0.8 m above the equilibrium position and is released with no initial velocity, no damping force acts on the system. If x(t) represents the displacement of the weight in meters, from the equilibrium point and taking upwards as the positive direction, an equation that describes the position of the weight as a function of time in seconds (gravity 9.8m/s^2) O a) (t) = 0.8 cos(t/78.4) O b) z(t) = 0.4 sen(t/78.4) %3D O c) z(t) = 0.8 (eVT84 +e tv784) ot/78.4 %3D O d) z(t) = 0.4 (ev784 + e -t/78.4
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A spring of constant k=8 N/m hanging from the ceiling is placed at its lower end with an object
of 1N which makes it remain in equilibrium, then the weight is pulled 0.8 m above the
equilibrium position and is released with no initial velocity, no damping force acts on the
system. If x(t) represents the displacement of the weight in meters, from the equilibrium point
and taking upwards as the positive direction, an equation that describes the position of the
weight as a function of time in seconds (gravity 9.8m/s^2)
O a) r(t) = 0.8 cos(tv/78.4)
O b) r(t) = 0.4 sen(t/78.4)
Oc) a(t) = 0.8 (ev784-
= 0.8 (V784 + e tVT8a)
-t/78.4
%3D
O d) z(t) = 0.4 (eV78.4 +eW784
%3D
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