A standard compaction test was performed in the laboratory and the results are tabulate follows: Trial Number 1 2 3 4 5 Moist Unit Weight (Ib/ft) 120.2 128.4 134.2 134.4 130.9 Moisture Content (%) 7.1 10.0 13.4 16.7 20.1 Determine the soil's maximum dry unit weight (drawing a plot may prove useful)

A standard compaction test was performed in the laboratory and the results are tabulate follows: Trial Number 1 2 3 4 5 Moist Unit Weight (Ib/ft) 120.2 128.4 134.2 134.4 130.9 Moisture Content (%) 7.1 10.0 13.4 16.7 20.1 Determine the soil's maximum dry unit weight (drawing a plot may prove useful)

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter6: Soil Compaction

Section: Chapter Questions

Problem 6.16P

See similar textbooks

Related questions

Q: Q1) the results of a standard compaction test are : w% 6.2 8.1 9.8 11.5 12.3 13.2 Ywet(KN/m³) | 16.9…

A: Given above table we have to find the 1- maximum dry density and OMP 2- plot zero void line

Q: Dynamic loading, Vibro static test, Standard proctor and modified proctor are tests to determine…

A: Soil boundaries give an idea of its compatibility with soil and water or both compounds. When the…

Q: 1) Find the maximum dry unit weight and optimum moisture content. 2) What is the moist unit weight…

A: (1) From the graph of standard proctor compaction test, we can see that - Maximum dry unit…

Q: A laboratory modified Proctor compaction test gave: optimum water content 16 % and maximum dry…

A: Volume of the soil = 1165 cm3 Mass of the soil = 2230 gm Mass density, ρ = 22301165 = 1.91 g/cm3…

Q: STANDARD PROCTOR TEST 1. Why does the soil need to be in the densest state when placed as an engine…

A: The soil need to be in the densest state when placed as an engineered fill because soil in densest…

Q: A field unit determination test for the soil, yielded the following data. Moisture content = 12% and…

A: The moisture content of soil in lab, w=12%The moist unit weight of soil in lab, γb =106 lbft3The…

Q: Note : Answer only four questions Q1 - A) Field density test performed on granular soil has given…

Q: Determine the liquid limit. LL = b. Determine the flow index. Flow index = Determine the liquidity…

A: Given Data: The plastic limit for the first trial is, PL1=16.2% The plastic limit for the second…

Q: The results of a standard Proctor test are given in the following table. Determine the maximum dry…

A: Volume of mold cm3, V weight of wet soil N, W Moisture Content, w γ =W/V(N/cm3) γd=γ/(1+w)…

Q: From the following data, solve for the degree of compaction. If this is for Item 201, Aggregate Base…

Q: Compute the dry unit weights (ydry) for each trial. Plot the compaction curve. From your compaction…

A: given-moisture content and bulk unit weight of silty sand. to find- maximum dry unit weight, optimum…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

Q: The results of a standard compaction test are shown in the table below: Mass of Mould + 2925 3095…

A: We knowρdry=ρwet1+wandat Zero air voidsρZAdry=Gρw1+wGtake G=2.7

Q: 1/30 1/30 3.88 3.87 1/30 3.87 1/30 3.77 . a. Determine the moist unit weight (ymoist) and dry unit…

Q: LL=25% PI=15% Cu=_____

A: From graph :D60=0.05mmD30=0.0026mmD10=0.0007mmFind uniformity coeff:Cu=D60D10=0.050.0007=71.4285Find…

Q: 6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water…

A: The water content corresponding to the maximum dry density of the soil is called optimum moisture…

Q: Problem 1: The table below present the results of a standard proctor test of a borrow pit soil. FEB…

Q: Q7: The Table 4 shows the results of a Standard Proctor Compaction test. Satisfactory Y N Based on…

Q: Proctor's compaction test for the maximum dry density of a certain soil gave the results as : 1.77…

Q: Problem Set No. 2. Modified Proctor Test is performed in a soil that is classified as CL and has a…

A: We knowγd=γwet1+wγZAV=GγW1+wGso,For…

Q: A compacted fill with a unit weight of 121 lb/ft^3 and a moisture content of 12.5% will be used for…

A: The dry unit weight of the soil in compacted fill is calculated as, γd=γb1+w=1211+0.125=107.56…

Q: Results of a proctor compaction test are as follows; Trial 1: wet density = 126 Ib/ft., moisture…

A: we know that wet density = dry density(1+w) trial no wet density(lb/ft3) w% dry density 1 126…

Q: Q1) the results of a standard compaction test are : w% 6.2 8.1 9.8 11.5 12.3 13.2 wet(KN/m3 16.9…

A: Given that Specific gravity of soil G = 2.7 Dry density = wet density/(1+w) w = water content For…

Q: 6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water…

A: Trial Proctor Mold Volume (cc) Mass (g) Moisture content Ybulk(g/cc) Ydry(g/cc) 1…

Q: The results of a standard Proctor test are given in the following table. Given: Mold volume = 1/30…

A: Note: Since you have asked multiple questions, we will solve the first question for you. If you want…

Q: 6. Following is the result of 8 trials of a standard proctor test. Determine the optimum water…

Q: |A Standard Proctor test was performed on a clayey Sand soil: the test results are shown below.…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three subparts…

Q: A sand cone test was conducted in the field. The mass of wet soil excavated from the hole is 3668.3g…

A: Mass of wet soil from hole (W1) =3668.3g Moisture of that soil (wc) = 17.2 % Weight of sand in hole…

Q: 6.4 The results of a standard Proctor test are given below. Determine the maximum dry unit weight of…

Q: Undisturbed soil sample was collected from the field in steel Shelby tubes for laboratory…

Q: The results of a standard Proctor test are given in Table Q2 below. Determine the maximum dry unit…

A: Given: The results of the standard proctor test are given below, Volume of Proctor mold…

Q: The results of a standard compaction test are shown in the table below Determine the maximum dry…

Q: The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the…

Q: The results of a standard Proctor test are given in the following table. a. Determine the maximum…

A: finding maximum dry density of each trial and maximum out of those will by maximum dry density and…

Q: The following data has been obtained from a standard Proctor test conducted on a silty clay soil.…

A: Note: As per the Bartleby guideline solution of the first three-part is provided. Optimum moisture…

Q: The nominal compactive effort (NCE) used for standard proctor test is 600 kJ/m3 300 kJ/m3…

A: Option 1 is correct 600 KJ/m3

Q: Table Q3(b): Sand cone replacement test result Item Value Unit kg/m kg kg kg kg % Calibrated dry…

A: The given data is: Item Value Unit Calibrated dry density of Ottawa sand (γsand) 1731 kg/m3…

Q: Atleast 3 laboratory apparatus for each of the following laboratory tests. 1. Determination of…

A: 1. Determination of moisture content of soil: Drying oven, Balance, Moisture can, Spatula 2.…

Q: 1) a) Derive the formula for falling head permeameter ( state all assumptions). for what type of…

A: 1. a) For deriving falling head permeability test, following things are need to be considered. A =…

Q: Bulk Unit Weight (kN/m3) 20.0 20.7 21.7 21.4 21.1 Water Content (%) 8.0 9.5 11.5 12.5 13.5 1.…

Q: A modified Proctor compaction test was carried out using a cylindrical mold with a 1000 ml volume.…

A: Wet densityρ=Wet massVolumeDry densityρd=ρ1+wZero AIr voidZAV DensityρZAV=ρwGS1+wGSExample:at…

Q: Table Q2(b)(i) shows the proctor compaction test results of bulk density and percentage of water…

Q: Question 4 In a standard compaction test on a soil (grain specific gravity of 2.67) the following…

Q: Q3. (a) The following results are obtained from a Standard Proctor compaction test: Mass of soil…

A: Given data, Specific gravity = 2.70 Volume V = 0.945×10-3 m3

Q: The compaction of a soil obtained from a standard compaction test is shown in the attached figure.…

A: Given:

Q: 1. The results of a lab compaction test using standard proctor procedure are shown in Figure 1.…

A: From figure γdmax=117.4lbft3OMC=11.8%

Q: A soil sample was taken from a site of a proposed borrow pits and sent to the laboratory for a…

A: The graph of standard proctor test is plotted between moisture content(%) and dry unit weightKn/m3…

Q: Unit weight determination Water content determination Mass of Mass of can and wet soil can and Mass…

A: We are authorized to answer three subparts at a time since you have not mentioned which part you are…

Q: A modified Proctor compaction test was carried out using a cylindrical mold with a 1000 ml volume.…

A: Formulaeρ=Wet massVolumeρdry=ρ1+wρzav=Gρw1+GwExample:at…

Q: The results of a standard compaction test for a soil having a value of (Gs = 2. 5) are shown in the…

A: Water Content (%) 6.2 8.1 9.8 11.5 12.3 13.2 Unit Weight (KN/m3) 16.9 18.7 19.5 20.5 20.4 20.1…

Concept explainers

Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.

Question

A standard compaction test was performed in the laboratory and the results are tabulated as
follows:
Trial Number
1
2
3
4
5
Moist Unit Weight (Ib/ft) 120.2 128.4 134.2 134.4 130.9
Moisture Content (%)
7.1
10.0 13.4 16.7 20.1
Determine the soil's maximum dry unit weight (drawing a plot may prove useful)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Read the question carefully and give me both a&b right solutions. A proctor compaction test in the laboratory on a borrow pit soil gives maximum unit weight of 19 kN/m3 and optimum water content of 11.5%. The bulk unit weight and water content of the soil in the borrow pit are 17.2 kN/m3 and 8.2%, respectively. A highway fill is to be constructed using this soil. The specifications require the fill to be compacted to 95% Proctor compaction. (a) What is the additional weight of water per unit volume required to bring the moisture content to the optimum value to achieve 95% Proctor compaction? (b) How many truckloads of borrow pit soil will be required for a 100,000 m3 highway embankment - assuming each truck has a capacity of 10 m3 ?
Enlist all the equipment used for compaction of subgrade, base and sub-base along with their efficiencies and also explain how will we check the compaction of base and sub-base layer at site?
A modified Proctor compaction test was carried out using a cylindrical moldwith a 1000 ml volume. Table 2 summarizes the results.a. Plot the compaction and ZAV curves (RD=2.75 and ρwater=1000 kg/m3).b. Determine the maximum dry density and the optimum moisture content.
identification 10 to 11 10. It is a characteristic of soil when liquidity index is greater than 1. 11. write the formula in determining relative compaction. this subject is related to geothecnical engineering (soil mech)
The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 95% of γd(max). Calculate and plot the 80% and 100% saturation lines.
The Table 4 shows the results of a Standard Proctor Compaction test. Based on the information provided, determine the following values. The maximum dry unit weight and the OMC.The degree of saturation at the maximum dry density if Gs = 2.70.What is the dry unit weight and the moisture range at 95% relative compaction (RC)?The degree of saturation at the maximum dry density if Gs = 2.70. Table 4: Results of a standard Proctor compaction test Trial No. 1 2 3 4 5 6 Moisture content, w (%) 6.2 8.1 9.8 11.5 12.3 13.2 Bulk unit weight (kN/m3) 16.9 18.7 19.5 20.5 20.4 20.1 Dry unit weight (kN/m3) 15.9 17.3 17.8 18.4 18.2 17.8
The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 90% of ꙋd (max).
For a granular soil, the following are given:●● Gs = 2.6●● Liquid limit on the fraction passing No. 40 sieve 5 20●● Percent retained on No. 4 sieve 5 20 Using Eqs. (5.4) and (5.5) attached , estimate the maximum dry density of compaction and the optimum moisture content based on the modified Proctor test.
A sample o f soi l compacte d accordin g t o a standar d Proctor test ha s a unit weight of 130.9 lb/ft 3 at 100 % compaction and at optimum water content o f 14% . What is the dryunit weight? If the voids become fille d with water what would be the saturated unit weight?Assume Gs = 2.67.
Laboratory compaction test results and fielddetermined in-place density (unit weight) results are reported in terms of dry density or unit weight and not wet density or unit weight. Outline the reasons for this procedure of reporting. (Hint: Consider the soil properties directly related to density or unit weight.)
A field density test has been conducted in a compacted fill that is currently under construction.The test results indicate a relative compaction of 101-103%, which made the constructionmanager believe the test must be incorrect. He believes it is impossible for the dry unit weightinthe field to be greater than the maximum dry unit weight from the Proctor compaction test.Explain why the relative compaction in the field could indeedbe greater than 100%.
Which of the following are standard procedures used for determining the field unit weight of compaction?I. Sand Cone MethodII. Rubber Balloon MethodIII. Nuclear MethodIV. Falling Head Test Method