A statistics practitioner took a random sample of 45 observations from a population whose standard deviation is 35 and computed the sample mean to be 108. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 90% confidence. Confidence Interval = C. Estimate the population mean with 99% confidence. Confidence Interval =

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Q: What would be the 95% confidence interval for the population mean if a sample of size 16 has a mean…

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Q: If n=400 and X=100​, construct a 95​% confidence interval estimate for the population proportion.

A: Given,x=100n=400sample…

Q: Use a t table to find the value of t to use in a confidence interval?

A: Note: you did not mention the information about the sample, for which t-value is to be obtained. So,…

Q: If X = 114, α= 20, and n = 33, construct a 99% confidence interval estimate for the population mean,…

A: Given data:  Sample Mean = 114 Population standard deviation = 20 Sample size = 33 Confidence level…

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Q: A If n=21, ¯x (x-bar)=34, and s=8, construct a confidence interval at a 98% confidence level. Assume…

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Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

A: The following assumptions are required for the large sample confidence interval about the mean to be…

Q: Determine the margin of error for a confidence interval to estimate the population mean with n = 21…

A: n = 21  s​ = 12.6 confidence interval = 80%.

Q: If n=24, x(x-bar)%=D30, and s=7, construct a confidence interval at a 98% confidence level. Assume…

A: The random variable X follows normal distribution. The sample size is 24. The sample mean is 30. The…

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Q: In a sample of 60 electric motors, the average efficiency (in percent) was 85 and the standard…

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Q: If 1850, 1970 is a confidence interval for a population mean. Find the value of the point estimator…

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Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

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Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

A: GivenPopulation standard deviation is knownThe variable under consideration is very close to being…

Q: A sample of 64 was taken from a population, with the mean of the sample being 25 and the standard…

A: It is given that  Sample mean = 25 Sample standard deviation = 2 Sample size = 64 Confidence level =…

Q: State whether each of the following changes would make a confidence interval wider or narrower.​…

A: Hey, since there are multiple questions posted, we will answer first question. If you want any…

Q: If n=12, x=47, and s=7, construct a confidence interval at a 98% confidence level. Assume the data…

A: According to the provided information,

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Q: A 99% confidence interval (with n = 1, 018) estimates the actual mean amount of internet usage a…

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Q: Suppose that you had collected the following sample data (in inches) on the diameters of tree…

A: Given that you had collected the following sample data (in inches) on the diameters of tree trunks,…

Q: 13, ¤(x-bar)=39, and s=16, construct a confidence interval at a 90% confidence level. Assume the…

A: From the given information, n=13 x-bar=39 s=16 Confidence level=90% Significance level=10%…

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: Assume that a sample is being used to estimate a population mean μμ. If n = 29, x¯ = 46, and s =…

A: From the provided information, Sample size (n) = 29 Sample mean (x̅) = 46 Sample standard deviation…

Q: In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96%…

A: Given information: n = 80 μ=50 96% confidence interval for the mean number of texts handled by teens…

Q: If X=72​, σ=13​, and n=66​, construct a 95​% confidence interval estimate of the population​…

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Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

A: The following assumptions are required for the large sample confidence interval about the mean to…

Q: A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.16 years…

A: Given: n = 25 X = 33.16 S = 9.89 Formula Used: Confidence Interval = X ± Sntn-1               {When…

Q: Assume that a sample is being used to estimate a population mean μμ. If n = 19, x¯ = 43, and s = 3,…

A:

Q: In each of Exercises, assume that the population standard deviation is known and decide whether use…

A: As per the sampling Distribution If the true population distribution of a random variable x  is…

Q: A 99% confidence interval for a population mean was reported to be 140 to 150. If population…

A: It is given that the 99% confidence interval for a population mean is 140 to 150. The population…

Q: If n=41, ¯x=39, and s=16, construct a confidence interval at a 99% confidence level. Assume the data…

A: Given that  Sample size (n) = 41 Sample mean (x¯) = 39 Sample standard deviation (s) = 16 Confidence…

Q: Find and interpret the 95% confidence interval for μ, if ¯y = 70 and s = 10, based on a sample size…

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Q: Find a Confidence interval for the true Population Proportions if n = 30,        x = 75, and the…

A: From the given information, X=75 and n=30.

Q: For each example, choose the confidence interval that has a larger margin of error. 1) OA 90%…

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Q: is: n=217, x 26.5 hg, s= 6.1 hg. Construct a confidence interval estimate of the mean. Use a 99%…

A: Given that  Sample size(n) = 217 sample mean (x¯) = 26.5 Sample standard deviation (s) = 6.1…

Q: f X=142​, σ=20​, and n=36​,construct a 99​% confidence interval estimate of the population​ mean, μ

A: Given that  sample mean (X) = 142 Population standard deviation (σ) =20​  Sample size (n) =36…

Q: answer a,b,c A random sample of 70 observations from a normally distributed population possesses a…

A: It is given that the summary statistics are as follows: Part (a): Confidence interval for µ:…

Q: "he 95% confidence interval for the population mean is 09.342 < µ< 10. 658 9. 336 < µ< 10. 664 09.…

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Q: If X=68​, σ=14​, and n=66​, construct a 95​% confidence interval estimate of the population​ mean, μ

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Q: (a) Find the sample mean and the sample standard deviation. (b) Construct and interpret a 91.85% and…

A: Here first find sample Mean and standard deviation

Q: find the t/α2 value for an 80% confidence interval for the mean when the sample size is 14

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Q: Develop a 95% confidence interval for the population slope if the following regression information…

A: Introduction: The 100 (1 – α) % confidence interval for the population partial slope coefficient, βi…

Q: Which of the following statements is true regarding the width of a confidence interval for a…

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Q: find the value: t a 2 and n = 15 for the 98% confidence interval for the mean.   t a 2 and n= 20…

A: a) Degrees of freedom=n-1=15-1=14   Then, at 98% confidence level, the value of t is 2.624. (From…

Q: how many samples out of 100 would you expect to not include the true population mean within their…

A: here given ,  confidence level =  90%  sample size  = 100

Q: If X=80​, σ=11​,and n=62​,construct a 95​% confidence interval estimate of the population​ mean, μ.…

A: Given,sample size(n)=62sample mean(x¯)=80standard deviation(σ)=11α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: A statistics student wants to conduct a study to determine the proportion of workers in Cititon who…

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Q: A political candidate is told by his polling organization that a 90% confidence interval for the…

A: We have given that the 90% confidence interval for the proportion of voters who support his…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.