If 1850, 1970 is a confidence interval for a population mean. Find the value of the point estimator of the population mean. Select one: O a. 1540 O b. 1910 O c. 1660 O d. 1795

Q: If X = 117, o=24, and n = 30, construct a 99% confidence interval estimate of the population mean, µ

A: It is given that Sample size n = 30 Sample mean = 117 Population SD = 24

Q: Consider the following dataset. Price (X) | Demand (Y) $49 $69 $89 $99 $109 124 95 71 45 18…

A: Linear regression: Suppose (x1, y1), (x2, y2)---(xn, yn) are n pairs of observations on variables X…

Q: If n=400 and X=100​, construct a 95​% confidence interval estimate for the population proportion.

A: Given,x=100n=400sample…

Q: d. ta and n = 8 for the 95% confidence interval for the mean. e. te and n= 21 for the 85% confidence…

A: Given that  d) Confidence level = 95% = 0.95 Sample size (n) = 8   We know that  Degrees of freedom…

Q: If X = 114, α= 20, and n = 33, construct a 99% confidence interval estimate for the population mean,…

A: Given data:  Sample Mean = 114 Population standard deviation = 20 Sample size = 33 Confidence level…

Q: If X=70​, σ=14​, and n=61​, construct a 99​% confidence interval estimate of the population​ mean,…

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Q: Construct the confidence interval for the population mean y. C=0.95, x= 16.7, o= 4.0, and n= 75. A…

A: Here, C=0.95, x=16.7, σ=4.0, and n=75.

Q: Construct the confidence interval for the population mean mean μ.  c=0.90​, x (x-bar)=16.2​, σ=10.0…

A: The 90% confidence interval for the population mean µ is calculated as follows:

Q: Find a 95% confidence interval for a mean, µ, where n = 324, x̄ = 2.7, s = .91, and se = .06.

A: Given: n = 324, x̄ = 2.7, s = .91, se = .06.

Q: If n 19, x =40, and s = 20, construct a confidence interval at a 80% confidence level.

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Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: In order to construct the 95% confidence interval, you choose which formula? O x ±1.645 × OT ±1.96 x…

A:

Q: Construct the indicated confidence interval for the population mean p using the t-distrib c=0.90, x=…

A: Solution: Given information: n= 9  Sample size x= 13.3  Sample mean s=2.0 Sample standard…

Q: What is the number of data values? O 50 O 78 O 120 49 O 76 How many degrees of freedom are used for…

A: data value 76

Q: Suppose a population is known to be normally distributed with a mean, μ, equal to 116 and a standard…

A: 68-95-99.7-rule: Let X be an observation from a normal distribution, having mean µ and standard…

Q: If n = 330 and X = 264, construct a 95% confidence interval for the population proportion, p.

A:

Q: If Xbar=81​,S=20​,and n=36​,and assuming that the population is normally​ distributed, construct a…

A:

Q: The 95% confidence interval for the population mean is . 09.336 < u < 10. 664 09.342 <µ < 10. 658

A: Given data,n=100x=10σ=4Find 95% CI?

Q: Find the standard error to estimate the population mean for each of the following. a. n = 17; 95%…

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Q: If X = 66, S = 16, and n = 64, and assuming that the population is normally distributed, construct a…

A: Given data: Sample mean = 66 Sample standard deviation = 16 Sample size = 64 Confidence level  = 95%…

Q: If [330, 610] is a confidence interval for the population mean. Find the margin of eror. Select one:…

A: The upper limit of the confidence interval is (U) = 610 The lower limit of the confidence interval…

Q: (c) How large would the sample need to be so that a 95% confidence interval would have a margin of…

A: Given that sample mean xbar=12.05 and population standard deviation=6.55 3) find sample size of…

Q: Construct the confidence interval for the population mean y. C= 0.90, x=16.6, o= 10.0, and n= 80

A: Here, C=0.90, x=16.6, σ=10.0, and n=80.

Q: A 95% confidence interval for mean was found to be (18.54, 21.22). What was the margin of error? O…

A: Given: confidence interval ( 18.54 , 21.22 ) Need to find margin of error(ME) .

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: Maria has data from a random sample of 16 subjects and is constructing a 95% confidence interval for…

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Q: Use the given data to construct a confidence interval of the requested level. X = 178, N=531,…

A: Given : Sample Size, n = N = 531 Number of successes, x = 178

Q: If X=99​, S=7​, and n=64​, and assuming that the population is normally​ distributed, construct a…

A:

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: If X = 147, o = 22, and n= 36, construct a 99% confidence interval estimate of the population mean,…

A:

Q: f n=200 and X=80​, construct a 99​% confidence interval estimate for the population proportion.

A:

Q: If Xbar=93​, σ=13​, and n=62​, construct a 99​% confidence interval estimate of the population​…

A: Given that  Sample size: n=62 Sample mean: x¯=93 Population standard deviation: σ=13 Confidence…

Q: If (220 ,230) is a confidence interval for the population mean p, then the point estimator in this…

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Q: Construct the confidence interval for the population mean p. c= 0.95, x 8.9, o=0.7, and n= 46

A: As the population standard deviation is known, we will use z distribution. The value of z at 95%…

Q: If n=41, ¯x=39, and s=16, construct a confidence interval at a 99% confidence level. Assume the data…

A: Given that  Sample size (n) = 41 Sample mean (x¯) = 39 Sample standard deviation (s) = 16 Confidence…

Q: Find a Confidence interval for the true Population Proportions if n = 30,        x = 75, and the…

A: From the given information, X=75 and n=30.

Q: If X bar = 75, S = 24, and n =36, and assuming that the population is normally distributed,…

A: Given X bar = 75,  S = 24,  and n =36,

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given data,n = 85x = 49 Sample proportion(p) = xn =4985=0.576Ƶ-value at 98% confidence is Ƶc = 2.326

Q: If X=99​, S=13​, and n=64​, and assuming that the population is normally​ distributed, construct a…

A: Mean = 99 Standard deviation = 13 Sample size = 64

Q: If you want to make a confidence interval for the mean with the TI-84, which of the following…

A: For the given statement Select the correct choice ?

Q: Construct a confidence interval for the population proportion p. n ? 144, x ? 86, 90% confidence

A: Given: Confidence level = 0.90 Sample size (n) = 144 x = 86 Sample proportion p^=xn=86144

Q: f X=142​, σ=20​, and n=36​,construct a 99​% confidence interval estimate of the population​ mean, μ

A: Given that  sample mean (X) = 142 Population standard deviation (σ) =20​  Sample size (n) =36…

Q: ch. The "confidence interval" lying between +1 SEM and -1 SEM would give us a “confidence level"…

A: The 68-95-99.7% (Empirical) Rule: For a normal distribution, the empirical rule (68-95-99.7% Rule)…

Q: "he 95% confidence interval for the population mean is 09.342 < µ< 10. 658 9. 336 < µ< 10. 664 09.…

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Q: if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came…

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Q: Given forecast errors of -5, 8, 8, and -3, what is the mean absolute deviation? O 2 O 4 6

A: The mean absolute deviation is obtained below: The given forecast error is -5, 8, 8 and -3. Let  E…

Q: If [1740, 1850] is a confidence interval for a population mean. Find the margin of error. Select…

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Q: In the formula for t, the "hypothesized value" is what you expect the t to be. the difference…

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Q: Find the value of −zα/2 that corresponds to a confidence level of 89.48​%.

A:

Q: If [1740, 1850] is a confidence interval for a population mean. Find the value of the point…

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