b) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1106 cycles)N :In practice, the load is not purely alternate, andthe minimum stress is omin =-132 MPa,the maximum stress is omax = 294 MPa.c) Calculate the new stress ratio R, the stress amplitude o, in MPaand the mean stress o, in MPa.The answers are acceptable with a tolerance of 1 MPa forstresses.R:MPaMPid) Calculate the corresponding life, in 10 cycles, (tolerance of 0.1106 cycles)N : A steel component is subjected to alternate cyclical loading.The steel follows Basquin's law for high cycle fatigue, o, x N = C,(where the stress amplitude is in MPa).Ignore the geometric detail and assume that Marin's modifyingfactors are all equal to 1.You are giventhe minimum stress ain = -213 MPa,the maximum stress omax = 213 MPa.The material data areTensile strength oUTS = 539 MPa,Basquin's constant c, = 875 MPa,Basquin's exponent a = 0.085.a) Calculate the stress ratio R, the stress amplitude o, in MPa andthe mean stress am in MPa.The answers are acceptable with a tolerance of 0.01 for R and of1 MPa the stresses.R:MPaMPаb) Calculate the corresponding life, in 10° cycles, (tolerance of 0.1106 cycles)N :

Answer: (a) Stress Ratio: -1 Amplitude Stress: 213 MPa Mean Stress: 0 MPa (b) The corresponding…

A steel component is subjected to alternate cyclical loading. The steel follows Basquin's law for high cycle fatigue, o, x N7 = C1 (where the stress amplitude is in MPa). Ignore the geometric detail and assume that Marin's modifying factors are all equal to 1. You are given the minimum stress omin = -213 MPa, the maximum stress omax = 213 MPa. The material data are Tensile strength ơUTS = 539 MPa, Basquin's constant c, = 875 MPa, Basquin's exponent a = 0.085. a) Calculate the stress ratio R, the stress amplitude o, in MPa and the mean stress am in MPa. The answers are acceptable with a tolerance of 0.01 for R and of 1 MPa the stresses. R : MPa MPa alculate th ding lifo Cucloc (toloran

A steel component is subjected to alternate cyclical loading. The steel follows Basquin's law for high cycle fatigue, o, x N7 = C1 (where the stress amplitude is in MPa). Ignore the geometric detail and assume that Marin's modifying factors are all equal to 1. You are given the minimum stress omin = -213 MPa, the maximum stress omax = 213 MPa. The material data are Tensile strength ơUTS = 539 MPa, Basquin's constant c, = 875 MPa, Basquin's exponent a = 0.085. a) Calculate the stress ratio R, the stress amplitude o, in MPa and the mean stress am in MPa. The answers are acceptable with a tolerance of 0.01 for R and of 1 MPa the stresses. R : MPa MPa alculate th ding lifo Cucloc (toloran

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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