A student carried out a titration using H2SO4 and KOH.  The balanced equation for the reaction is: H2SO4 (aq) + 2 KOH (aq)  -->  K2SO4 (aq)  +  2 H2O (l) The student determined that 0.227 mol KOH were used in the reaction.  How many moles of H2SO4 would have been needed to react with all of this KOH?

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Q: mole

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