1.) Hydrocyanic acid [HCN(aq)] can be neutralized by potassium hydroxide [KOH(aq)].Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?

Answered: be neutralized by potassium hydroxide…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter15: Acid–base Equilibria

Section: Chapter Questions

Problem 98AP

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1.) Hydrocyanic acid [HCN(aq)] can be neutralized by potassium hydroxide [KOH(aq)].

Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.
For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?

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Step 1

In this question we have to balance the following chemical equation and calculate the grams of KOH required to neutralize the given amount of acid.

$S o l W e h a v e t o b a l a n c e t h e c h e m i c a l e q u a t i o n o f n e u t r a l i z a t i o n o f H y d r o c y a n i c a c i d [H C N (a q)] w i t h p o t a s s i u m h y d r o x i d e [K O H (a q)] R e a c t i o n H C N (a q) + K O H (a q) \to K C N (s a l t) + H_{2} O (l) 1 m o l e 1 m o l e 1 m o l e H e r e, 1 m o l e o f H C N r e q u i r e 1 m o l e o f K O H t o f o r m o n e m o l e o f s a l t K C N$

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