A student doing the colligative properties experiment was curious to try using 3.00 m of the NaCl solution instead of the 1.50 m indicated in the manual. How will the experimental van't hoff factor of the original experiment be compared to the modified method? O a. i of the 1.50 m NaCl will be lower than that of the 3.00 m solution O b. Indeterminate O c. i of the 1.50 m NaCl will be higher than that of the 3.00 m solution O d. i of the 1.50 m NaCl will be equal to that of the 3.00 m solution

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.82QE: The freezing point of a 0.031-m solution of copper(II) sulfate in water is 0.075 C. (a) Calculate...
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A student doing the colligative properties experiment was curious
to try using 3.00 m of the NaCl solution instead of the 1.50 m
indicated in the manual. How will the experimental van't hoff factor
of the original experiment be compared to the modified method?
a. i of the 1.50 m NaCl will be lower than that of the 3.00 m
solution
O b. Indeterminate
O c. i of the 1.50 m NaCl will be higher than that of the 3.00 m
solution
O d. i of the 1.50 m NaCl will be equal to that of the 3.00 m
solution
Transcribed Image Text:A student doing the colligative properties experiment was curious to try using 3.00 m of the NaCl solution instead of the 1.50 m indicated in the manual. How will the experimental van't hoff factor of the original experiment be compared to the modified method? a. i of the 1.50 m NaCl will be lower than that of the 3.00 m solution O b. Indeterminate O c. i of the 1.50 m NaCl will be higher than that of the 3.00 m solution O d. i of the 1.50 m NaCl will be equal to that of the 3.00 m solution
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