A student drew a circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you agree with the student's condusion? Why or why not? Complete the explanation. = QR V. Since PR PQ = PT PS by the Given: PQ PS.Then PQ (select) PR = PQ + QR and PT = PS +ST,PQ +QR =(select) v.Since PQ = PS, QR = (select) .Therefore, QR (select) v congruent to ST.So, I (select) v v,PR PS = PT PS, and so PR = (select) v. Since %3D %3D %3D %3D

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter4: Quadrilaterals
Section4.3: The Rectangle, Square, And Rhombus
Problem 42E: a Argue that the midpoint of the hypotenuse of a right triangle is equidistant from the three...
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A student drewa circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you
agree with the student's conduslon? Why or why not? Complete the explanation.
P.
Since PR PQ = PT PS by the
v,PR PS PT PS, and so PR = (select) . Since
Given: PQ PS.Then PQ= QR v
(select)
PR = PQ+QR and PT = PS+ST,PQ +QR = (select) v. Since PQ = PS,QR = (select) v.Therefore,
QR (select) v congruent to ST. So, I (select)
%3D
%3D
Transcribed Image Text:Question Example Step by Step A student drewa circle and two secant segments. He concluded that If PQ PS, then QR ST.Do you agree with the student's conduslon? Why or why not? Complete the explanation. P. Since PR PQ = PT PS by the v,PR PS PT PS, and so PR = (select) . Since Given: PQ PS.Then PQ= QR v (select) PR = PQ+QR and PT = PS+ST,PQ +QR = (select) v. Since PQ = PS,QR = (select) v.Therefore, QR (select) v congruent to ST. So, I (select) %3D %3D
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