A student experimenting with a pendulum counted the number of full swings the pendulur in 20 seconds for various lengths of string. Her data are shown below.

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question d but of 48 what is the answer for with 4.

A student experimenting with a pendulum counted the number of full swings the pendulum
in 20 seconds for various lengths of string. Her data are shown below.
27
37.
X= Length (in.)
Number of swings
6.5
9
11.5
14.5
18
21
24
30
22
20
17
16
14
13
13
12
11
10
(a) Explain why a linear model is not appropriate for using the Length of a pendulum to pre
Number of Swings in 20 seconds.
Herplot is uot linear
re-.94 2both are
but residual plot s
a clear
parterm
pe= .89 S pretty good
(b) Re-express the data to straighten the scatterplot.
Vs.
log X vs .logy
r°= . 96
re-.995
rE.982
logx
patteru to
residuals
residuals show
no clear pallern
(c) Create an appropriate model.
outlier
log(# of swiugs)= -45 (1og(leugta) + 1. 721
(d) Estimate the number of swings for a pendulum with a 48-inch string.
log g=-45(1ng (49) 1.72|
log =.9644
9= 9.214 suwings
y = 10-9644
%3D
Transcribed Image Text:A student experimenting with a pendulum counted the number of full swings the pendulum in 20 seconds for various lengths of string. Her data are shown below. 27 37. X= Length (in.) Number of swings 6.5 9 11.5 14.5 18 21 24 30 22 20 17 16 14 13 13 12 11 10 (a) Explain why a linear model is not appropriate for using the Length of a pendulum to pre Number of Swings in 20 seconds. Herplot is uot linear re-.94 2both are but residual plot s a clear parterm pe= .89 S pretty good (b) Re-express the data to straighten the scatterplot. Vs. log X vs .logy r°= . 96 re-.995 rE.982 logx patteru to residuals residuals show no clear pallern (c) Create an appropriate model. outlier log(# of swiugs)= -45 (1og(leugta) + 1. 721 (d) Estimate the number of swings for a pendulum with a 48-inch string. log g=-45(1ng (49) 1.72| log =.9644 9= 9.214 suwings y = 10-9644 %3D
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