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Social ScienceA student in the laboratory connects a 13 Ω resistor, a 29 Ω resistor, and a 41 Ω resistor in series and then connects the arrangement to a 41-V dc source.(a) How much current is in the circuit?___ A(b) How much power is expended in the circuit?___ W
A student in the laboratory connects a 13 Ω resistor, a 29 Ω resistor, and a 41 Ω resistor in series and then connects the arrangement to a 41-V dc source.
___ A
(b) How much power is expended in the circuit?
___ W
Expert Answer
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(a)Since the resistors are connected in series, the net resistance of the circuit will be equal to the sum of the individual resistances. The net resistance of the circuit is R= 13 Ω+ 29 Ω+41 Ω =83 Q Here, R is the net resistance of the circuit. The equation for the current in the circuit is given by V I R Here, I is the current and V is the potential difference Substitute the numerical values in the above equation 41 V I 83 Q 0.494 A
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