Question
Asked Nov 23, 2019
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A student mixes 92.9 g of water at 89.3°C with 35.1 g of water at 23.9°C in an insulated flask. What is the final temperature of the combined water?

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Expert Answer

Step 1

Given data:

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Initial temperature (T ) of 92.9 g(m, ) of water = 89.3 °C Initial temperature (T2) of 35.1 g (m, ) of water 23.9 °C

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Step 2

Since heat transfers from 92.9 g of water to 35.1 g of water, the heat transfer (q) must be equal in magnitude but opposite sign. The final temperature of combined water is calculated as shown below.

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m, Caar (AT)= -m Casr (AT) m(T,-T) -m(T, -T) тТ, - тТ, %3 -т,Т, +т,T, ater тT, + m,T, — тТ, + т,T, т,Т, + m,Tz Т, т, + т, (1)- Where, T, is the final temperature of combined water. m is the mass of first water sample m2 is the mass of second water sample T is the initial temperature of first water sample T2 is the initial temperature of second water sample.

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Step 3

Substitute the given data in equation (I) to calculate the ...

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тТ, + m,T, т, т, + т, 92.9 g.89.3°C+35.1 g 23.9 °C (92.9 g +35.1 g) 9°C 8295.97 838.89 128 9134.86 128 = 71.36 °C

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