A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)₂ solution that is needed. 53.0 mL 53.0 L Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter4: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 47E
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A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing
the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)2 solution
that is needed.
53.0 mL
53.0 L
X
Answer Bank
0.23 M
0.14 M
0.14 mL
0.23 mL
=
mL
Transcribed Image Text:A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)2 solution that is needed. 53.0 mL 53.0 L X Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL
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