A student reacts benzene, C6H6, with bromine, Br2, to prepare bromobenzene, C,H5Br, and HBr. C6H6 Br2 --> C6H5B + HBr What is the theoretical yield of bromobenzene in this reaction when 35.2 g of benzene reacts with 67.9 g of bromine? grams Which chemical is the limiting reactant? Select an answer If the actual yield of bromobenzene was 21.5 g, what was the percent yield? % Submit Question

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Q: A student reacts benzene, C6H6, with bromine, Br2, to prepare bromobenzene, C6H5Br, and HBr. C6H6 +…

A: Given 39.3 g of benzene reacts with 61.8 g of bromine actual yield of bromobenzene is 31.7g

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Q: A student reacts benzene, C6H6, with bromine, Br2, to prepare bromobenzene, C6H5Br, and HBr. C6H6 +…

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Q: A student reacts benzene, C6H6, with bromine, Br2, to prepare bromobenzene, C6H5Br, and HBr. C6H6 +…

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Q: A student reacts benzene, C6H6, with bromine, Br2, to prepare bromobenzene, C6H5Br, and HBr. C6H6 +…

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UV Visible Spectroscopy

Spectroscopy refers to the absorption or emission of light or other radiations by matter. When a substance or chemical absorbs light or radiation, they reach an excited state followed by de-excitation or emission of the light or radiation forming distinct spectra. UV-visible spectroscopy or  ultraviolet-visible refers to the absorption and emission in the ultraviolet and visible regions of the electromagnetic spectrum.