A study of 420,019 cell phone users found that 140 of them developed cancer of the brain or nervous system. Prior to this study of cell phone​ use, the rate of such cancer was found to be 0.0448​% for those not using cell phones. Complete parts​ (a) and​ (b).       a. Use the sample data to construct a 95​% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.   enter your response here​%

Q: A department store finds that in a random sample of 200 customers, 60% of the sampled customers had…

A:

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: In a four-year psychedelic-mushroom experiment, 93 of the 300 subjects reported experiencing “strong…

A: Obtain the point estimate for the percentage of all people who experience “strong or extreme fear”…

Q: a 99% confidence interval

A: Confidence interval :  Confidence interval measures the degree of uncertainty. or it is the…

Q: In another pre-election poll, a pollster finds that 438 out of 600 people polled favor, Smith.…

A: Given, X = 438 N = 600 The sample proportion is given by:

Q: A study of 420,055 cell phone users found that 137 of them developed cancer of the brain or nervous…

A: From the provided information, Sample size (n) = 420055 Out of which 133 developed cancer of the…

Q: 3. A survey of 2,950 Filipinos showed that 2,655 trust the Supreme Court decisions on legal issues.…

A: Let X be the number of trust the supreme court decision on legal issues  n be the sample size  Given…

Q: In a poll conducted by the Gallup organization in April 2013, 48% of a random sample of 1022 adults…

A: Obtain the 95% confidence interval for the proportion of all U.S. adults in April 2013 who felt that…

Q: In a survey of 2344 ​adults, 715 say they believe in

A: Given that there are 2344 adults and 715 say they believe in UFOs. Consider the sample proportion,…

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: In one of the studies, it was found that, in a random sample of 261 married persons, 135 were…

A:

Q: In a study of government financial aid for college​ students, it becomes necessary to estimate the…

A: formula for the sample size :

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: 11) In a Gallup poll, 1011 adults were asked if they consume alcoholic beverages and 64% of them…

A: (11) Obtain the 90% confidence interval estimate of the proportion of all adults who consume…

Q: A Gallup poll of 1001 Americans age 18 and over conducted in May of 2013 found that 80% of the…

A: Solution: From the given information, p-hat=80% and the margin of error is 3.2%.

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

A: Given that Sample size n= 500  Favorable cases x=160 Sample proportion p^=x/n

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: The random variable cyber bullied follows normal distribution. The sample size is 14795. The number…

Q: Suppose that you will be taking a random sample from a population and that you intend to find a 95%…

A: Solution: The confidence interval for the population mean is calculated by using the following…

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: We have given that,  Favorable cases (X) = 2219 and sample size   (n) = 14795. Then,  We will find…

Q: In a survey with human resources managers, 71% of respondents thought they should hire new staff…

A: Given information: Denote the population proportion of all respondents who thought that they should…

Q: An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars…

A:

Q: In a survey of 1200 adults, 562 said that they plan to watch the next Olympics on television. Using…

A: Formula for calculating Margin of error :  ME=Zα/2 * √p̂(1-p̂)/n

Q: Between 27 April 2020 and 10 May 2020, Gallup surveyed a random sample of 8,712 U.S. adults…

A: e) Given information: p^=0.24n=8712 Confidence level is 95%. From the standard normal table, the…

Q: In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students…

A: Given data is appropriate for testing of hypothesis. Because it is a large sample test for single…

Q: A local health center noted that in a sample of 400 patients, 80 were referred to them by the local…

A: From the provided information, Sample size (n) = 400 From which 80 were referred to them by the…

Q: Suppose that a random sample of 60 horror movies containing 100 character deaths was collected.…

A: we must identify zα/2 and the margin of error, E. The confidence level is stipulated to be 0.95,…

Q: b. In a random sample, 165 of 500 persons given a flu vaccine experienced some discomfort. i.…

A: Given that  Sample size n =500 Favorable cases x =165 Sample proportion p^=x/n  =165/500 =0.33

Q: Suppose that you have obtained data by taking a random sample from a population and that you intend…

A: 95% percent confidence interval will give more accurate estimate of µ than 99% confidence interval.…

Q: 9. A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

A:

Q: A study of 420,010 cell phone users found that 0.0319% of them developed cancer of the brain or…

A: Solution: Given information: n= 420010 Sample size  p^=0.0319100= 0.000319 Sample Proportion

Q: Alma is estimating the proportion of students in her school district who, in the past month, read at…

A: From the given information, n=50 and x = 32.

Q: b.Suppose a similar survey will be given to vaccine-eligible people in Canada by Canadian health…

A: Given data, p=0.5 E=0.02 z-value at 95% confidence is Zc=1.96 n=?

Q: From a recent survey, the 90% confidence interval estimate of the proportion of students who have…

A: Note: As per the guidelines only one question can be answered. Kindly,  resubmit the question with…

Q: studying an anomaly in chick embryos, 50 fertilized eggs were injected with a treatment on the…

A: Given Data Sample Size, n = 50 Number of successes, x = 50-12=  38.0 Significance…

Q: A study was being done to estimate the proportion of students who receive financial aid. If the…

A:

Q: 4. A random sample of 64 bicycle-riding adults in Portland indicated that 24 always wore a helmet…

A:

Q: For many years businesses have struggled with the rising cost of health care. But recently, the…

A: Obtain the margin of error. The value of the margin of error is obtained below as follows: Use…

Q: Construct a 95% confidence interval for the population proportion of students who graduate within…

A: The sample size is n = 400 And the number of students who graduate within six years, X = 108 The…

Q: Exercise 3 An employment counselor found that in a sample of 100 unemployed workers, 65% were not…

A: Given that : 1) sample size = 49  Mean = $ 23.45 S. D = $ 2.80 90% confidence interval.

Q: study of 420,048 cell phone users found that 137 of them developed cancer of the brain or nervous…

A: Given that, n=420048 x=137 p¯=xn=137420048=0.000326 90% C.I. for p P(-z<p<z)=0.90 z=1.645 […

Q: 5. A phase three clinical trial for a new medication proposed to treat depression has 1191…

A: From the provided information, x is 759 and n is 1,191. The sample proportion is p hat is x/n =…

Q: In a preelection poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the…

A: We need to construct the 95% confidence interval for the population proportion. We have given the…

Q: In a study of academic procrastination, the authors of a paper reported that for a sample of 431…

A:

Q: A farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to…

A: Solution: Let X be the number of blooms that yield marketable strawberries and n be the sample…

Q: Do younger people use Twitter more often than older people? In a random sample of 316 adult Internet…

A:

Q: A study of 420 comma 026   cell phone users found that 140   of them developed cancer of the brain…

A: Find z-critical value:

Q: A survey of 800 women shoppers found that 17% of them shop on impulse. what is 98% confidence…

A:

Q: A researcher studying reaction time of drivers states that, "A 95% confidence interval for the mean…

A: Givena 95% confidence interval for the meantime it takes for driver to apply the brakes after seeing…

Q: In a survey of 500 potential jurors, one study found that 350 were regular watchers of at least one…

A: