(a) Suppose f(x) and g(x) are both continuous functions on [a, b] and that f(x) < g(x) for all æ in [a, b]. Use the Comparison Property for Definite Integrals to show that fave < Jave. (b) Suppose that minimum value of f(x) on [a, b] is m, and the maximum value of f(x) on [a, b) is M, i.e. fmin = m and fmax = M. Use part (a) to show that m< fave < M.

College Algebra (MindTap Course List)
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ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
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Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
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Recall that the average value of a continuous function f on the closed interval [a, b]
is given by

fave
f (x)dx.
- a.
In high school, you probably learned that the average value of a collection of numbers is
always between the maximum and minimum number from the collection. The same is true
for functions! The goal of this problem is to justify this.
(a) Suppose f(x) and g(x) are both continuous functions on [a, b] and that f(x)< g(x) for
all a in [a, b]. Use the Comparison Property for Definite Integrals to show that
fave < Jave.
(b) Suppose that minimum value of f(x) on [a, b] is m, and the maximum value of f(x) on
[a, b] is M, i.e.
fmin = m and fmax = M.
Use part (a) to show that
m< fave < M.
Transcribed Image Text:fave f (x)dx. - a. In high school, you probably learned that the average value of a collection of numbers is always between the maximum and minimum number from the collection. The same is true for functions! The goal of this problem is to justify this. (a) Suppose f(x) and g(x) are both continuous functions on [a, b] and that f(x)< g(x) for all a in [a, b]. Use the Comparison Property for Definite Integrals to show that fave < Jave. (b) Suppose that minimum value of f(x) on [a, b] is m, and the maximum value of f(x) on [a, b] is M, i.e. fmin = m and fmax = M. Use part (a) to show that m< fave < M.
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