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StatisticsQ&A LibraryA survey of 1060 randomly selected US teens ages 13-17 found that 605 of them say they have made a new friend online.(a) Find and interpret a 90% confidence interval for the proportion, p, of all US teens who have made a new friend online.(b) Give the best estimate for p and give the margin of error for the estimate.(c) Use the interval to determine whether we can be 90% confident that more than half of US teens have made a new friend online.Question

Asked Mar 26, 2020

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A survey of 1060 randomly selected US teens ages 13-17 found that 605 of them say they have made a new friend online.

(a) Find and interpret a 90% confidence interval for the proportion, p, of all US teens who have made a new friend online.

(b) Give the best estimate for p and give the margin of error for the estimate.

(c) Use the interval to determine whether we can be 90% confident that more than half of US teens have made a new friend online.

Step 1

Given:

Step 2

(a)

From the standard normal table, the *z*-score at 90% confidence level is 1.645.

The 90% confidence interval for the proportion of all US teens that have made a new friend online can be constructed as:

There is 90% probability that the proportion of US teens that have made a new friend online lies between 0.545 and 0.596.

Step 3

(b)

**The point estimate is:**

**The margin of error can be calculated as:**

...

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