A symmetrical vertical curve joining a +3% and a -4 % grades is to be designed for 100 km/hr. If the tangents intersect at station (200+00) at an elevation of 30m, determine the stations and elevations of the BVC and EVC.
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- a +7% grade meets a -4% grade at the vertex V with elevation of 30m and stationing of 2+000. It is required to connect the two tangents with an asymmetrical vertical parabolic curve, 60m on the back tangent and 40m on the forward tangent. Compute the elevation at station 1+950m.A 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the summit.A 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -1% and final grade is +1% b) determine the highest and the lowest points on this vertical curve by using the K-value.
- Determine the minimum length of a sag vertical curve between a -1.06% grade and + 2.1% for a road with 110 kph design speed. The vertical curve must provide 200 m sight distancea 2300 ft equal tangent crest vertical curve is currently designed for 60 mph.this curve connects an initial grade of +3.5% and a negative grade, final grade what is the min k-value under 60 mph design speed use the min-k value as your deisn value determine A and G2 where is the highest point along curveAn equal-tangent vertical curve is to be constructed between grades of +1%(initial) and -1%(final). The final point of vertical curvature is at station 0+500 and at elevation 100m. Indicate if this vertical curve is safe for a design speed of 70 km/h regarding stopping sight distance.
- A vertical parabolic curve is to be used under a grade-separation structure. The curve is 250 m long and the minus grade of 3.8 percent intersects the plus grade of 5.4 percent at station of 0+120.424. Calculate the low point of the curve if the intersection at station 0+120.424 is at elevation 230.085 m.1. A parabolic curve has an ascending grade of 4% which meets a descending grade of 3% at sta. 1+ 180 whose elevation is at 320 m. Compute the elevation of the PVT(point of vertical tangency) if the length of the curve is 280 mA 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and elevation 450 m. The initial grade is -5% c) determine the desing speed for this vertical curve( in 10 km/h increments )
- 1. A vertical sag parabolic curve has tangent grades of -1.7% and +2.3%. If the length of curve is 135 m, compute the sight distance. 2. A vertical sag parabolic curve has tangent grades of -2% and +3%. Compute the length of curve if the required sight distance is 178m.A sag vertical curve is to be designed to join a -5% grade to a +2% grade. If the design speed is 65 km/h, determine the minimum length of the curve that will satisfy all criteria. Assume a=3m/squared and perception-reaction time = 2.5 sec.A 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft. The curve starts at station 15+25. The initial grade is +5% and the final grade is -3%. Determine the elevation of the middle point of the curve.