A table of values is given for Y, =f(x). Determine whether the intermediate value theorem guarantees that the function has a zero on the given interval. Y, = 25x*+48x-241x-329x+317 Y1 -4 1105 -3 - 136 -2 27 -1 382 317 1 - 180 - 521 Part 1 of 4 (a) Y (Choose one) have a zero on the interval -4, -3]. does does not

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 78E
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Part 2 of 4
(b) Y, (Choose one)
have a zero on the interval -3, -2].
does
does not
Part 3 of 4
(c) Y, (Choose one) ▼
have a zero on the interval-2, -1].
Part 4 of 4
(d) Y, (Choose one) V
have a zero on the interval -1, 0|.
Transcribed Image Text:Part 2 of 4 (b) Y, (Choose one) have a zero on the interval -3, -2]. does does not Part 3 of 4 (c) Y, (Choose one) ▼ have a zero on the interval-2, -1]. Part 4 of 4 (d) Y, (Choose one) V have a zero on the interval -1, 0|.
A table of values is given for Y, =f(x). Determine whether the intermediate value theorem guarantees that the function has a zero on the given interval.
= 25x*+48x – 241x- 329x+317
Y1
-4
1105
- 3
- 136
-2
27
382
317
1
- 180
2
- 521
Part 1 of 4
(a) Y, (Choose one)
have a zero on the interval-4, -3|.
does
does not
Transcribed Image Text:A table of values is given for Y, =f(x). Determine whether the intermediate value theorem guarantees that the function has a zero on the given interval. = 25x*+48x – 241x- 329x+317 Y1 -4 1105 - 3 - 136 -2 27 382 317 1 - 180 2 - 521 Part 1 of 4 (a) Y, (Choose one) have a zero on the interval-4, -3|. does does not
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