A tank is partitioned by a divider as shown in the figure below. The tank is filled by water (SG=1) and mercury (SG=13.55) and the cross-sectional area ratio AR/AL=5:1. a) Find the gage pressure in the air trapped on the left side b) To bring the water and mercury free surface even, what pressure would the air on the left to be pumped to c) If the right side is sealed airtight, what pressure would the air on the left to be pumped to to bring the water and mercury free surface even (assume the air trapped on the right side behaves isothermally, i.e., the ideal gas law applies)

Elements Of Electromagnetics
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Please explain part b and c

1. A tank is partitioned by a divider as shown in the figure below. The tank is filled by water
(SG=1) and mercury (SG=13.55) and the cross-sectional area ratio AR/AL=5:1.
a) Find the gage pressure in the air trapped on the left side
b) To bring the water and mercury free surface even, what pressure would the air on the
left to be pumped to
c)
If the right side is sealed airtight, what pressure would the air on the left to be pumped
to to bring the water and mercury free surface even (assume the air trapped on the
right side behaves isothermally, i.e., the ideal gas law applies)
Cross-sectional
Area A₁
Cross-sectional
Area AR
1m
2.9 m
Air
Water
Mercury
3 m
3 m
Transcribed Image Text:1. A tank is partitioned by a divider as shown in the figure below. The tank is filled by water (SG=1) and mercury (SG=13.55) and the cross-sectional area ratio AR/AL=5:1. a) Find the gage pressure in the air trapped on the left side b) To bring the water and mercury free surface even, what pressure would the air on the left to be pumped to c) If the right side is sealed airtight, what pressure would the air on the left to be pumped to to bring the water and mercury free surface even (assume the air trapped on the right side behaves isothermally, i.e., the ideal gas law applies) Cross-sectional Area A₁ Cross-sectional Area AR 1m 2.9 m Air Water Mercury 3 m 3 m
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