A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station's 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch 55 or 11 p.m. News? 18 or less 19 to 35 36 to 54 Older Total Yes 50 45 65 80 240 No 200 205 185 170 760 Total 250 250 250 250 1,000 (a) Let Pj. P2. P3. and P4 be the proportions of all viewers in each age group who watch the station's 11 p.m. news. If these proportions are equal, then whether a viewer watches the station's 11 p.m. news is independent of the viewer's age group. Therefore, we can test the null hypothesis Hg that p1. P2. P3- and Pa are equal by carrying out a chi-square test for independence. Perform this test by setting a = .05. (Round your answer to 3 decimal places.) x^2 = HO: independence so Reject Do not reject (b) Compute a 95 percent confidence interval for the difference between P1 and P4. (Round your answers to 3 decimal places. Negative amounts should be indicated by a minus sign.) 95% CI: [

A television station wishes to study the relationship between viewership of its 11 p.m. news program and viewer age (18 years or less, 19 to 35, 36 to 54, 55 or older). A sample of 250 television viewers in each age group is randomly selected, and the number who watch the station's 11 p.m. news is found for each sample. The results are given in the table below. Age Group Watch 55 or 11 p.m. News? 18 or less 19 to 35 36 to 54 Older Total Yes 50 45 65 80 240 No 200 205 185 170 760 Total 250 250 250 250 1,000 (a) Let Pj. P2. P3. and P4 be the proportions of all viewers in each age group who watch the station's 11 p.m. news. If these proportions are equal, then whether a viewer watches the station's 11 p.m. news is independent of the viewer's age group. Therefore, we can test the null hypothesis Hg that p1. P2. P3- and Pa are equal by carrying out a chi-square test for independence. Perform this test by setting a = .05. (Round your answer to 3 decimal places.) x^2 = HO: independence so Reject Do not reject (b) Compute a 95 percent confidence interval for the difference between P1 and P4. (Round your answers to 3 decimal places. Negative amounts should be indicated by a minus sign.) 95% CI: [

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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