Question

Asked Nov 5, 2019

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A tennis player tosses a tennis ball straight up and then catches it after 1.58 s at the same height as the point of release.

(a) What is the acceleration of the ball while it is in flight?

(b) What is the velocity of the ball when it reaches its maximum height?

(c) Find the initial velocity of the ball.

m/s

(d) Find the maximum height it reaches.

m

magnitude | m/s^{2} |

direction |

(b) What is the velocity of the ball when it reaches its maximum height?

magnitude | m/s |

direction |

(c) Find the initial velocity of the ball.

m/s

(d) Find the maximum height it reaches.

m

Step 1

Part (a):

When the ball is thrown upwards the only force acting on it is force of gravitation. Thus, the acceleration of the ball is acceleration due to gravity. The direction of acceleration is downwards due to effect of gravitational force and its magnitude is same as acceleration due to gravity.

Step 2

Part (b):

When the ball is moving upward the acceleration is decreasing with increase in height. At maximum height the ball stops and starts moving downwards. Thus, the velocity of the tennis ball at maximum height is zero. The direction of the velocity will be downward at maximum height because after this point the ball will start moving downwar...

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