A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 98.0 percent pure. How many grams are needed to prepare 0.50 L of a 41.0 mM solution?

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A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 98.0 percent pure. How many grams are needed to prepare 0.50 L of a 41.0 mM solution?

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Step 1

Given,

Molar mass of tetraphenyl phosphonium chloride = 342.39 g/mol

Percentage of purity of tetraphenyl phosphonium chloride = 98.0 %

Molarity = 41.0 mM = 0.041 M

Volume = 0.50 L

Number of moles of tetraphenyl phosphonium chloride needed to prepare 0.50 L of a 0.041 M(mol/L) solution, can be calculated as:

Step 2

Grams of tetraphenyl phosphonium chloride can be calculated as:

Step 3

The calculated mass (7.02 g) is the pure mass of tetraphenyl phosphonium chloride required. But, it is given that purity of tetrapheny...

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