The reaction 2 NO(g) + O₂(g) --> 2 NO₂(g) proceeds through the following mechanism:(a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction?O Rate = k [NO] [0₂]O Rate = k [NO]² [0₂]O Rate = k [NO] [0₂]²O Rate = k [NO]¹/2 [0₂]O Rate = k [NO] [0₂]¹/2O Rate = k [NO]²O Rate = k [NO]² [0₂]1/2(b) What would the rate law be if the first step of this mechanism were rate-determining?O Rate = k [NO] [0₂]O Rate = k [NO]² [0₂]O Rate = k [NO] [0₂]²1O Rate = k [NO]¹/2 [0₂]O Rate = k [NO] [0₂]1/2O Rate = k [NO]²O Rate = k [NO]² [0₂]¹/2O Rate = k [NO]2 NO(g) --> N₂O2(9)N₂O2(g) + O2(g) -->> 2 NO₂(g)

(a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction? Rate = k [NO] [0₂] Rate = k [NO]² [0₂] Rate = k [NO] [0₂]² Rate = k [NO]¹/2 [0₂] O Rate = k [NO] [0₂]¹/2 Rate = k [NO]² Rate = k [NO]² [0₂]1/2 (b) What would the rate law be if the first step of this mechanism were rate-determining? Rate = k [NO] [0₂] Rate = k [NO]² [0₂] Rate = k [NO] [0₂]² Rate = k [NO]¹/2 [0₂] O Rate = k [NO] [0₂]1/2 Rate = k [NO]² Rate = k [NO]² [0₂]¹/2 Rate = k [NO]

(a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction? Rate = k [NO] [0₂] Rate = k [NO]² [0₂] Rate = k [NO] [0₂]² Rate = k [NO]¹/2 [0₂] O Rate = k [NO] [0₂]¹/2 Rate = k [NO]² Rate = k [NO]² [0₂]1/2 (b) What would the rate law be if the first step of this mechanism were rate-determining? Rate = k [NO] [0₂] Rate = k [NO]² [0₂] Rate = k [NO] [0₂]² Rate = k [NO]¹/2 [0₂] O Rate = k [NO] [0₂]1/2 Rate = k [NO]² Rate = k [NO]² [0₂]¹/2 Rate = k [NO]

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter12: Chemical Kinetics

Section: Chapter Questions

Problem 3RQ: One experimental procedure that can be used to determine the rate law of a reaction is the method of...

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